At a seaport, the depth of the water during the day can be found using the equation h = 6.0 cos ( 27) + 14 27-8) 12.4 where h is the depth of water in feet and t is the number of hours after midnight. At 8:00 pm what will be the water's height? 15.23 feet O 19.77 feet 19.88 feet O 10.40 feet

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Chapter2: Analytic Trigonometry
Section2.3: Solving Trigonometric Equations
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3 of 21
At a seaport, the depth of the water during the day can be found using the equation
h = 6.0 cos ( 2T-
(t-8) + 14
12.4
where h is the depth of water in feet and t is the number of hours after midnight.
At 8:00 pm what will be the water's height?
15.23 feet
19.77 feet
O 19.88 feet
10.40 feet
Transcribed Image Text:3 of 21 At a seaport, the depth of the water during the day can be found using the equation h = 6.0 cos ( 2T- (t-8) + 14 12.4 where h is the depth of water in feet and t is the number of hours after midnight. At 8:00 pm what will be the water's height? 15.23 feet 19.77 feet O 19.88 feet 10.40 feet
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