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At first: count = Result = Now: count = count: Result = Now: count = Result = Result = Current value of count: Now, value of count:

At first: count = Result = Now: count = count: Result = Now: count = Result = Result = Current value of count: Now, value of count:

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Trace the above code and complete the following output of the program At first: count = Result = Now: count = count: Result = Now: count = Result = Result = Current value of count: Now, value of count:
Transcribed Image Text:Trace the above code and complete the following output of the program At first: count = Result = Now: count = count: Result = Now: count = Result = Result = Current value of count: Now, value of count:
Given int result, int count and the following code snippet 1. count = 3; 2. printf ("At first: count = $d", count); 3. 4. result = 2* ++count; 5. printf ("\nResult = %d ", result); printf ("\nNow: count = $d \n\n", count); 6. 7. 8. 9. count = 4; 10. printf("count: %d ", count); 11. 12. result = 2*count++; 13. printf ("\nResult printf ("\nNow: count = $d ", result); = $d \n\n", count); 14. 15. 16. 17. result *= -3* (result + count)/3; 18. 19. printf ("\nResult = $d ", result); 20. 21. result /= ++count*2; 22. printf ("\nResult = %d ", result); printf ("\nCurrent value of count: %d ", count); 23. 24. 25. 26. count %= result + (count + 3); 27. printf ("\nNow, value of count: $d ", count);
Transcribed Image Text:Given int result, int count and the following code snippet 1. count = 3; 2. printf ("At first: count = $d", count); 3. 4. result = 2* ++count; 5. printf ("\nResult = %d ", result); printf ("\nNow: count = $d \n\n", count); 6. 7. 8. 9. count = 4; 10. printf("count: %d ", count); 11. 12. result = 2*count++; 13. printf ("\nResult printf ("\nNow: count = $d ", result); = $d \n\n", count); 14. 15. 16. 17. result *= -3* (result + count)/3; 18. 19. printf ("\nResult = $d ", result); 20. 21. result /= ++count*2; 22. printf ("\nResult = %d ", result); printf ("\nCurrent value of count: %d ", count); 23. 24. 25. 26. count %= result + (count + 3); 27. printf ("\nNow, value of count: $d ", count);
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