At my local bar, it always takes at least two minutes to serve a customer, and it can take much longer. The time in minutes that it takes to serve a customer may be modelled by a continuous random variable T with probability density function f(t) 64 t≥ 2.
At my local bar, it always takes at least two minutes to serve a customer, and it can take much longer. The time in minutes that it takes to serve a customer may be modelled by a continuous random variable T with probability density function f(t) 64 t≥ 2.
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Hi. Please help. I need to calculate the
![At my local bar, it always takes at least two minutes to serve a customer, and it can take much
longer. The time in minutes that it takes to serve a customer may be modelled by a continuous
random variable T with probability density function
f(t) = 64, t> 2.
The C.d.f for random variable T is,
wwwwww
16
F(t) = 1- t> 2.
Use the p.d.f. f(t) to calculate the mean and variance of the time taken
to serve a customer.
Mean
u= E(T)
11
=
=
= √₂ + f (6) dt
11
=
64
dt
So 64E-5 alt
:(-16) - (-1²)
0 + 1
= 1 minute.
[-16] 2
= [-]일
AS
(im I
∞0 + 0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5cd9e192-0e90-49ce-a5f5-5dbdfc960c65%2Fd629aa2f-fab2-4b94-8746-947202cc2fca%2Fr8ktpsg_processed.png&w=3840&q=75)
Transcribed Image Text:At my local bar, it always takes at least two minutes to serve a customer, and it can take much
longer. The time in minutes that it takes to serve a customer may be modelled by a continuous
random variable T with probability density function
f(t) = 64, t> 2.
The C.d.f for random variable T is,
wwwwww
16
F(t) = 1- t> 2.
Use the p.d.f. f(t) to calculate the mean and variance of the time taken
to serve a customer.
Mean
u= E(T)
11
=
=
= √₂ + f (6) dt
11
=
64
dt
So 64E-5 alt
:(-16) - (-1²)
0 + 1
= 1 minute.
[-16] 2
= [-]일
AS
(im I
∞0 + 0
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