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At t;= 4.00 s, the acceleration of a particle moving at constant speed in counterclockwise circular motion is (7.00 m/s²)i + (3.00 m/s²)j At t₂-7.00 s (less than one period later), the acceleration is = (3.00 m/s²)-(7.00 m/s²) The period is more than 3.00 s. What is the radius of the circle? Number Units

At t;= 4.00 s, the acceleration of a particle moving at constant speed in counterclockwise circular motion is (7.00 m/s²)i + (3.00 m/s²)j At t₂-7.00 s (less than one period later), the acceleration is = (3.00 m/s²)-(7.00 m/s²) The period is more than 3.00 s. What is the radius of the circle? Number Units

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At t₁ = 4.00 s, the acceleration of a particle moving at constant speed in counterclockwise circular motion is (7.00 m/s²)i + (3.00 m/s²) = At t27.00 s (less than one period later), the acceleration is = (3.00 m/s²)-(7.00 m/s²); The period is more than 3.00 s. What is the radius of the circle? Number Units
Transcribed Image Text:At t₁ = 4.00 s, the acceleration of a particle moving at constant speed in counterclockwise circular motion is (7.00 m/s²)i + (3.00 m/s²) = At t27.00 s (less than one period later), the acceleration is = (3.00 m/s²)-(7.00 m/s²); The period is more than 3.00 s. What is the radius of the circle? Number Units
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