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Q: 554. What safe value of W can be applied to the beam loaded as shown in Fig. P-554 if o, < 60 MPa…
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- Determine the smallest value of yield stress Fy, for which a W-, M-, or S-shape from Part 1 of the Manual will become slender. To which shapes does this value apply? What conclusion can you draw from your answer?A simply supported beam has a maximum moment equal to 25 KN.m. The beam has a width of 200 mm and a depth of 250 mm and is made up of 80% grade Narra. Use dressed dimension by reducing its dimensions by 10 mm. What is the actual bending stress of the beam in MPa? Blank 1 (use two decimal places)The dimensions of a rectangular beam are limited to b = 300 mm and effective depth, d = 700 mm. Using f’c = 28 MPa, long bar fy = 415 MPa, calculate the required amount of tensile reinforcement so that a tensile strain of 0.005 is attained under a sustained ultimate bending moment of 1,200 kN.m. Compression bars centroid is 70 mm from beam edge. 5.353 3,839 4,387 6,180
- A channel shape is used to support the loads shown on the beam. The dimensions of the shape are also shown. Assume LAB=3ft , LBC=9ft , P=2050lb , w=1200lb/ft , b=12in , d=5in , and t=0.875in. Consider the entire 12-ft length of the beam and determine a)the maximum compression bending stress at any location along the beam and b)the maximum tension bending stress at any location along the beam.Answer in ksi, rounded-off to 2 decimal places.A simply supported beam 4 m long is carrying a variable load of w = 0 KN/m at the left support and w = 15 KN/m at the right. The beam has a width of 200 mm and a depth of 250 mm and is made up of 80% grade Narra. Use dressed dimension by reducing its dimensions by 10 mm. What is the actual bending stress of the beam in MPa? Blank 1 (use two decimal places, no need for unit)A simply supported concrete beam 6m long is reinforce with four-28 mm diamgram tension bars. The beam has a width of 300mm and over all depth of 400.the steel covering to the centroid of the renforcement is 70 mm fc=30mpa and fy 418mpa A .draw a stress diagram B.compute for the ultimate capacity of the beam
- Rigid bar ABCD is loaded and supported as shown. Steel [E = 29900 ksi] bars (1) and (2) are unstressed before the load P is applied. Bar (1) has a cross-sectional area of 0.81 in.2 and bar (2) has a cross-sectional area of 0.46 in.2. After load P is applied, the strain in bar (1) is found to be 770 με. Assume L1=55 in., L2=78 in., a=31 in., b=31 in., and c=36 in. Determine: (a) the stresses in bars (1) and (2). (b) the vertical deflection vD of point D on the rigid bar. (c) the load P.Calculate the stresses in members AB, DF, and BD. Given:FAB = 51.22 kN (C)FDF = 50 kN (C)FBD = 32.98 kN (C)d = 0.05 mRigid bar ABCD is loaded and supported as shown. Steel [E = 28400 ksi] bars (1) and (2) are unstressed before the load P is applied. Bar (1) has a cross-sectional area of 0.75 in.2 and bar (2) has a cross-sectional area of 0.45 in.2. After load P is applied, the strain in bar (1) is found to be 850 μεμε. Assume L1=53 in., L2=79 in., a=34 in., b=33 in., and c=30 in. Determine:(a) the stresses in bars (1) and (2).(b) the vertical deflection vD of point D on the rigid bar.(c) the load P.
- •Timber beamSafe working stress = 25 MPaCross-section dimensions:height = 119 mm,width = 66 mmProving ring number 293. Steel beam Safe working stress = 200 MPa Cross-section dimensions:external height = 149 mm,external width = 50 mm,wall thickness = 3.0 mm,Proving ring number 1522.1)Calculate safe max bending moment in the central part of the beam using Mmax = (I)(max stress)/(D/2)2) calculate Safe applied force in the proving ring or tie rod, assuming a symmetrical setup as in the photowith a ‘lever arm’ of 600 mmWhat is the midspan value of EI δ for the beam loaded as shown? Draw fbd.The initial compressive force of a steel column can be determined by using the Euler's Critical Load Formula. The x-axis has an unbraced length of L meters which is fixed at the top and bottom supports to prevent sidesway. The y-axis has an unbraced length of L/2 meters due to the bracing at mid-height. The properties of the column are the following A=8,453mm2 , Ix=178,046,682mm4 , Iy=21,982,846mm4 ,Fy=345MPa. Calculate the minimum length, L of the column in millimeters without exceeding the proportionality limit, fs=328.8MPa. Express your answer in 2 decimal places. Please box the final answer.