AWWTP effluent of 0.011 m^3 /s and a BOD5 of 590 mg/L discharges into a river. The river has flow of 1.7 m^3 Is., the BOD5 of the river is 0.6 mg/L. The BOD rate constants (k1) are 0.115 day^-1 for the waste water and 3.7 day^-1 for the river. Calculate the initial ultimate BOD (Lo) after mixing. = 9.270 mg/I z 6.452 mg/I - 8.233 mg/l = 7.345 mg/I

AWWTP effluent of 0.011 m^3 /s and a BOD5 of 590 mg/L discharges into a river. The river has flow of 1.7 m^3 Is., the BOD5 of the river is 0.6 mg/L. The BOD rate constants (k1) are 0.115 day^-1 for the waste water and 3.7 day^-1 for the river. Calculate the initial ultimate BOD (Lo) after mixing. = 9.270 mg/I z 6.452 mg/I - 8.233 mg/l = 7.345 mg/I

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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