(b) 2х? + 5х — 12 (d) х* + 27х (Г) х'у — 4ху (а) 4х? — 25 - - (c) х3 — Зх? — 4х + 12 3x? - (е) Зх3/2 — 9x!/2 + бх-1/2

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Polynomials

Try substituting 1. You will get 6 and not 0. Try other real values also. What About -2? Let us check.