Answered: B-4 B-5 B-6 LL = 3.25 kN/m LL = 4.70…

Engineering

Civil Engineering

B-4 B-5 B-6 LL = 3.25 kN/m LL = 4.70 kN/m DL = 13.32 kN/m DL = 16.69KN/m 4500 3500 3800

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: STATICALLY INDETERMINATE BEAMS Using Double Integration Method and/or Moment Area Method, answer…

Q: A t Com 8 C ,2m x 4m MI + 5m P₁ OTA 6 5m

Q: e the magnitude of the re

A: Given:- FB= 700 N, FC= 560 N To find:- the magnitude of the resultant force and the direction…

Q: B-1 В-2 В-3 LL = 3.25 k LL = 2.88 kN/m DL = 24.78 kN/m DL = 25.40 kN/m

Q: What is the moment MBC and MABin KN-m? 2 decimal places

Q: PROBLEM For the beam loaded as shown, do the following 1. Determine the values of shear and moment…

A: NOTE : Since you have posted a question with multiple sub-parts, we will solve the first three…

Q: PROBLEM #4: Draw the shear and moment diagram of the simply supported beam. Also, determine the…

Q: Analysis of Statically Determinate Beams roblem 03: raw the shear and moment diagrams for the…

Q: 48 kN/m 32 kN/m A TB C - 9 m - 6 m

Q: STATICALLY INDETERMINATE BEAMS Using Double Integration Method and/or Moment Area Method, answer -4…

Q: Compute the value of EIS at point B of the simply supported beam ABC using moment area method. 600…

A: Find EIδ Value at B using moment area method

Q: |В-1 |В-2 В-3 LL = 3.25 k LL = 2.66 kN/m DL = 24.78 kN/m DL = 23.4 kN/m

Q: 1. The frame shown carries the following loads as shown in the figure. Assume EI = 86,400 kN – m²…

A: Support D settles by 40 mm Support B settles by 25 mm. As all members are assumed to be axially…

Q: Refer on the given beam below. Using moment distribution method, determine the reactions (KN) at the…

Q: Determine the magnitude of the moment MA for the cantilever beam, where w = 5 kN/m, M = 15 kN-m, and…

A: Explanation : Moment MA at the fixed end of the cantilever beam can be calculated using equation…

Q: 400 Ib 300 Ib 150 o/ft 50 1b /Ht 12 fb 2孔 12-ft 4fb RA

Q: Construct moment diagrams for the beam using superposition method. 67 kN 500 | 450 N/m 135 kN–m D C…

Q: 300 N/m 2.7 kN • m +3 m -- 3 m-+ 3 m--3 m-

A: Elastic curve equation: The equation of the elastic curve is determined by differentiating the…

Q: В-1 В-2 B-3 LL = 2.66 kN/m LL = 2.88 kN/m DL = 23.4 kN/m DL = 25.40 kN/m

Q: An indeterminate beam loaded a uniformly distributed load from A to B, from B to C, a linearly…

Q: 21 01 A structure is to be built as shown supporting a uniform load of 18 kN/m. The location for the…

A: Let C is at distance of a m from A.

Q: Determine shear and moment equations of the beam shown. Neglect horizontal reactions since there are…

Q: Draw the bending moment diagram for the frame loaded shown using the moment distribution method C /2…

A: We have to draw the bending moment diagram using moment distribution method

Q: В-4 B-5 В-6 LL = 5.33 kN/m LL = 3.25 kN/m DL = 13.32 kN/m DL = 29.62 kN/m 4500 3500 3800

Q: 50 kN/m 20 kN/m IMANTIHalinomm Kam * A D B 4 m 3 m 4 m RA Rp

Q: The frame is loaded as shown. Using Moment Distribution Method, determine the support reaction.…

Q: |В-4 B-5 В-6 LL = 5.33 kN/m DL = 29.62 kN/m 4500 3500 3800

Q: For the continuous beam shown below, if the distribution factor D.F are already calculated and…

Q: *11-12. Determine the moments acting at A and B. Assume A is fixed supported, B is a roller, and C…

A: Determine the moments acting at A and B.Assume A is fixed supported, B is a roller, and C is a pin.…

Q: Determine shear and moment equations of the beam shown. Neglect horizontal reactions since there are…

Q: By comparing the result between Slope Deflection Equation and Modified Moment Distribution Method,…

A: Given A beam Required By comparing the result between Slope Deflection Equation and ModifiedMoment…

Q: For the following beam, Which of the following are the shear and moment functions? 20 kN/m 3m O a.…

Q: 9 kN 12 kN E 5 m F BO 5m K G C -5 m L H D 4 m + 4 m

A: A frame arrangement is given in figure as shown above and it has been asked in the question to…

Q: P2 = 20 kN P1 = 30 kN W̟ = 12.5 kN/m Wp = 7.5 kN/m WL = 10.5 kN/m : 4.5 kN/m WD В 3 m 2.5 m 10 m 8 m

Q: A 6-m simple beam is carrying a uniform load of 25 kN/m over the entire beam with two-point loads of…

A: A simply supported beam is simply supported by the supports and is stable in nature. The only way in…

Q: Given a simple beam 40 ft. long, construct influence dia- grams and compute the maximum values due…

A: Solution: ILD Drawn Below:

Q: В-1 В-2 B-3 LL = 2.66 kN/m DL = 23.4 kN/m

Q: For AC Beam Below Determine Moments and Reactions at Supports by Moment Distribution Method. 10 kN/m…

Q: Using the Cantilever Method, determine the Moment Reaction at point B of the given Frame. Answer…

Q: The beam in the figure below is to be loaded with 20kN single axle load, a uniformly distributed…

Q: 2. Determine the intensity w, and then draw the shear and moment diagrams for the ski. Find also the…

Q: Rigid frame loaded with a uniformly varying load on member BC and a horizontal concentrated load of…

Q: Using moment distribution method, determine resulting end moment at A. 3 k/it 2 k/ft fitttttt! B -15…

Q: Draw B.M.D For SP Beam (EI Constant) by Using Moment Distribution Method. 8.6 kN/m 5.2 kN/m E I S E…

A: Given data 2 UDL Length Flexural rigidity

Q: 1. Draw the bending moment diagram for the continuous beam ABCD loaded as shown. The relative moment…

Q: For the frame shown, the distributed loading is applied at EFGH. All the vertical members (AE, IE,…

A: The Moment at GH is only due to Fixed end moment at GH.

Q: P= 180 kN w =10 kN/m B 5m 3m 4m 6mi D A

A: (1). Fixed End Moments: MAB=MBA=0MBC=-wL212-Pab2L2=-10×8212-180×5×3282=-179.89…

Q: * The beam shown supported by fix support from left side and a roller from the right side, and an…

Q: B 30 kN ΕΙ 2EI 4 m² 8 m -8 m- -12 m MOMENT DISTRIBUTION METHOD. Solve the member (internal) moments…

A: Solve the member (internal) moments of the continuous beam shown.

Question

Use the moment distribution method to determine the end moments and reactions at support for the continuous beams.

Assume fixed support at the left end of the beam and the rest of the supports may be assumed hinge or roller.
(UNIFORM LOAD)

PLEASE PROVIDE ME THE

DF AND FEM

В-4
B-5
В-6
LL = 3.25 kN/m
LL = 4.70 kN/m
DL = 13.32 kN/m
DL = 16.69kN/m
4500
3500
3800

200
4500
3500
750/ 1250
1800
B1
B2
B3
T&B
A=4.81
BEDROOM 2
ELEV.
BOMELEV.
+3.6m
ELEV.
f3.6m
A -3.06
+ 3.6m
MASTE
BEDRO
A=3.59
B4
B5
B6
Ta
MOMM DIA RSB A
B20
B22
B28

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

FIXED END MOMENTS

VIEW

DISTRIBUTION FACTORS

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

W1 = 10 KN/m a = 2m b = 3m
A rectangular gravity dam has a height 5 m. It retains 3 mdeep of water. Calculate the minimum width of the concrete damthat is necessary to prevent the dam from sliding. The specificgravity of the concrete is 2.4 and the coefficient of frictionbetween the base of the dam and the foundation is 0.50. Use factorof safety against sliding of 1.5. a. 3.214 m b. 2.345 mc. 1.125 m d. 1.254 m
Three independent lines oflevels are run from BM1 to BM2. Route A is 6km long, route B is 4 km long and route C is 8km long. By route A, BM2 is 82.27 m aboveBM1, by route B, BM2 is 82.40 m above BM1and by route C, BM2 is 82.10 m above BM1.20. Compute the probable difference inelevation between BM1 and BM2. a. 82.29 m c. 82.56 mb. 82.95 m d. 82.63 m
W1=2.0 kN/m W2= 1.3 kN/m
) Evaluate the stability of the 3 m wide x 4 m deep (into the page) x 2 m tall block with a SG of 0.5 shown below in seawater (SG = 1.03) by determining the displaced depth and the metacenter height.
GEOTECHNICAL ENGINEERINGFor the clay slope, on rock determine the FS. If Kh = 0.4 (seismic factor)data H = 16 m β = 30 ° Ysat = 20 kn / m3 Cu = 50 kn / m2
q=3.15 kn/m , a=3.15m
given data : the slope of the dam 2v/1h so the height of the dam 12 m/ the all width of the dam will be 6 m (the width of the rectangular part is b-6)/ the depth of the dam 60m coefficient of sheer resistance = 0.75 gamma concrete 24 KN/m2 tailwater level of water converted into the channel directly behind the dam is 0.5 m (you will see that detail right of the picture drawn) the strip is 1 m (a force acting from water to dam ) height of the dam 12m height of water in the dam 10 m questions? 1- calculate all force in the picture W1/W2/u(uplift force)/Fh1/Fh2?(horizontal and vertical forces must all be calculated ) 2-Determine the dam weight needed to achieve a sliding factor of safety of 1.5 3-Determine the moments imposed at the dam toe. 4-Determine the dam weight needed to achieve an overturning factor of safety of 2. 5-Assuming that the dam downstream is with a slope of 1V/2H determine the dam base width to satisfy the stability requirements? 6-At the dam bottom an emergency…
Verticle load is 258 kN as opposed to 25*8kN - Apologies
W1 = 10 kN/m P2 = 60 kN a = 2 c = 5 M1 = 35 kNm
A wooden cylinder (sg=0.61) is placedvertically in oil with specifc gravity of 0.85. Determine the metacentric height.
A rectangular channel 1 m wide, Chézy C = 60, S = 0.0064, carries 1 m/s. Determine the velocity.