b) Due to hydraulic shock, the pipe ruptured resulting in release of liquid ammonia into the atmosphere. Liquid ammonia immediately flashes in the surrounding at ambient temperature, Tamb = 298 K and atmospheric pressure, Patm = 101325 Nm‍². Accordingly, i) starting from first principles, and stating any assumptions made, show that the mass flow rate of liquid ammonia escaping through the ruptured pipe upon failure is given by: 2(Pf - Patm) Qm=pArCou² + (1) Ρ Where: Qm = the mass flow rate, kgs¨¹ p = the fluid density, kgm³ A₁ = the pipe rupture area, m² = Co discharge coefficient u = fluid velocity inside the pipe, ms¨¹ Pf = fluid pressure inside the pipe, Nm²² Patm atmospheric pressure, Nm²

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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b) Due to hydraulic shock, the pipe ruptured resulting in release of liquid ammonia into the
atmosphere. Liquid ammonia immediately flashes in the surrounding at ambient temperature,
Tamb = 298 K and atmospheric pressure, Patm
= 101325 Nm². Accordingly,
starting from first principles, and stating any assumptions made, show that the
mass flow rate of liquid ammonia escaping through the ruptured pipe upon failure
is given by:
i)
2(P, — Расm)
(1)
Qm = pA,Co |u²
+
Where:
Qm = the mass flow rate, kgs
p = the fluid density, kgm3
A, = the pipe rupture area, m?
Co = discharge coefficient
u = fluid velocity inside the pipe, ms-1
= fluid pressure inside the pipe, Nm2
P;
Patm = atmospheric pressure, Nm³
n-2
Transcribed Image Text:b) Due to hydraulic shock, the pipe ruptured resulting in release of liquid ammonia into the atmosphere. Liquid ammonia immediately flashes in the surrounding at ambient temperature, Tamb = 298 K and atmospheric pressure, Patm = 101325 Nm². Accordingly, starting from first principles, and stating any assumptions made, show that the mass flow rate of liquid ammonia escaping through the ruptured pipe upon failure is given by: i) 2(P, — Расm) (1) Qm = pA,Co |u² + Where: Qm = the mass flow rate, kgs p = the fluid density, kgm3 A, = the pipe rupture area, m? Co = discharge coefficient u = fluid velocity inside the pipe, ms-1 = fluid pressure inside the pipe, Nm2 P; Patm = atmospheric pressure, Nm³ n-2
Additional Information:
Density of liquid ammonia at 240 K and 104800 Nm2 = 681.75 kgm3
Discharge coefficient for release = 0.61
Ruptured pipe release area = 0.003 m2
Molecular weight of ammonia = 17 gmol-1
Specific heat ratio of ammonia = 1.35
Gas constant= 8.314 Jmol-' K-'
Ambient temperature = 298 K
Pipe length = 10 m
Pipe diameter = 0.304 m
Transcribed Image Text:Additional Information: Density of liquid ammonia at 240 K and 104800 Nm2 = 681.75 kgm3 Discharge coefficient for release = 0.61 Ruptured pipe release area = 0.003 m2 Molecular weight of ammonia = 17 gmol-1 Specific heat ratio of ammonia = 1.35 Gas constant= 8.314 Jmol-' K-' Ambient temperature = 298 K Pipe length = 10 m Pipe diameter = 0.304 m
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