B Question : consider the 2nd virial equation of state == 1 + = = · The second virial cofficient of mixture is given by for (0₂ (1) and CH3Br (2) at 2971 and 500 kiper :- B11 = -394·1X106 m²/mal B12= -567-3X10 m/mot B 23-411x6 m²/mal B=X²₁ B₁₁ + 2 X ₁ X ² B ₁ 2 + x ²₂ B₂ 2 al Explain the physical meaning for the 2nd virial cofficient. b) Determine the value of the and virial cafficient, B. e) petermine the moteur volume V.

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