b) Solve the differential equation found in a) to derive the general equation that describes the amount of y present at time t for exponential growth or decay. c) In problem b) the solution should be: y = y,e where yo is the original amount at t = 0, and k > 0 is growth, k < 0 is decay, and k is the rate of growth (or decay). Now answer the following from the perspective of the differential equation found in a): i) Why is yo called the original amount? ii) Why is it called growth when k > 0? i) Why is it called decay when k < 0? iv) Why is it k called the growth/decay rate? v) Why is k also called the constant of proportionality?

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3) The general equation for exponential growth and decay is derived from the differential
equation described with the following sentence:
The rate of change of variable y is proportional to the value of y.
This statement describes a differential equation. The differential equation can be solved to
find the particular solution as follows:
y= y,e*
With (0,yo) as the initial condition given. This is called exponential growth, and the formula
is commonly found in algebra 2 and precalculus textbooks. See below for example.
The formula below is the solution to the differential equation that describes – the rate of
change of P is proportional to P, where k is the growth/decay rate, and the initial amount is
Po
Transcribed Image Text:3) The general equation for exponential growth and decay is derived from the differential equation described with the following sentence: The rate of change of variable y is proportional to the value of y. This statement describes a differential equation. The differential equation can be solved to find the particular solution as follows: y= y,e* With (0,yo) as the initial condition given. This is called exponential growth, and the formula is commonly found in algebra 2 and precalculus textbooks. See below for example. The formula below is the solution to the differential equation that describes – the rate of change of P is proportional to P, where k is the growth/decay rate, and the initial amount is Po
b) Solve the differential equation found in a) to derive the general equation that describes
the amount of y present at time t for exponential growth or decay.
c) In problem b) the solution should be:
y= y,e*
where yo is the original amount at t = 0, and k >0 is growth, k< 0 is decay, and k is the
rate of growth (or decay).
Now answer the following from the perspective of the differential equation found in a):
i) Why is yo called the original amount?
ii) Why is it called growth when k > 0?
iii) Why is it called decay when k< 0?
iv) Why is it k called the growth/decay rate?
v) Why is k also called the constant of proportionality?
Transcribed Image Text:b) Solve the differential equation found in a) to derive the general equation that describes the amount of y present at time t for exponential growth or decay. c) In problem b) the solution should be: y= y,e* where yo is the original amount at t = 0, and k >0 is growth, k< 0 is decay, and k is the rate of growth (or decay). Now answer the following from the perspective of the differential equation found in a): i) Why is yo called the original amount? ii) Why is it called growth when k > 0? iii) Why is it called decay when k< 0? iv) Why is it k called the growth/decay rate? v) Why is k also called the constant of proportionality?
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