B) The steel rod having a diameter of 2Z mm is subjected to an internal moment of 4Y0 Nm as shown in Figure Q2(b). Take: Z=0 Y =0 (i) Determine the stress created at points A, B, and C. Note that moments of inertia for the circular area can be determined by 1= (ar* )/ 4. M = 4Y0 Nm Radius = 0.5(2Z) mm Figure Q2(b) (0.5 × DD )' Q2 b (i ) x10-“ m* 4 4 - Mc MN /m* @MPa (Compression) I Mc MN /m² @ MPa (Tension) I -M -400x 0.5(20) sin 45 = x10 m |MPa (Compression)

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Q2
B) The steel rod having a diameter of 2Z mm is subjected to an internal moment of 4Y0 Nm as
shown in Figure Q2(b).
Take:
Z=0
Y =0
(i)
Determine the stress created at points A, B, and C.
Note that moments of inertia for the circular area can be determined by
I= (ar' )/ 4.
y A
M= 4ΥΟ Nm
45°
Radius = 0.5(2Z) mm
Figure Q2(b)
I= 7 (0.5× DD
Q2 b (i )
x10-“m*
4
4
- Mc,
MN /m² @ MPa
(Compression)
I
MC
MN / m² @ MPa
(Tension)
I
- Mc,
-400x 0.5(20) sin 45 =
x10“ m*
|MPa (Compression)
I
Transcribed Image Text:Q2 B) The steel rod having a diameter of 2Z mm is subjected to an internal moment of 4Y0 Nm as shown in Figure Q2(b). Take: Z=0 Y =0 (i) Determine the stress created at points A, B, and C. Note that moments of inertia for the circular area can be determined by I= (ar' )/ 4. y A M= 4ΥΟ Nm 45° Radius = 0.5(2Z) mm Figure Q2(b) I= 7 (0.5× DD Q2 b (i ) x10-“m* 4 4 - Mc, MN /m² @ MPa (Compression) I MC MN / m² @ MPa (Tension) I - Mc, -400x 0.5(20) sin 45 = x10“ m* |MPa (Compression) I
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