Please Solve it in SQL (part b) • Using the online database provided by W3schools.com (check the link).• For each query screenshot the SQL code and the result table.• Arrange everything in 1 file by the query number.• Add a cover page & Upload your work to Blackboard as a PDF file.• https://www.w3schools.com/sql/trysql.asp?filename=trysql_select_allA) Work on the “Products" table and apply the queries mentionedbelow.• Display the average price of products in each category (name theresult column as “AVG Price"), also display the category ID• Display the most expensive product name and ID that came fromsupplier number 6.B) Use subquery to answer the following questions: Work on the“Products", “Suppliers", and “Categories" tables as needed.• List the contact name and phone number of the supplier that provideus with the cheapest product.• List full information of the category that has the largest number ofproducts

EXPLANATION: The SELECT command is used to select the required fields from the particular table or…

B) Use subquery to answer the following questions: Work on the “Products", “Suppliers", and “Categories" tables as needed. • List the contact name and phone number of the supplier that provide us with the cheapest product. • List full information of the category that has the largest number of products

B) Use subquery to answer the following questions: Work on the “Products", “Suppliers", and “Categories" tables as needed. • List the contact name and phone number of the supplier that provide us with the cheapest product. • List full information of the category that has the largest number of products

A Guide to SQL

9th Edition

ISBN:9781111527273

Author:Philip J. Pratt

Publisher:Philip J. Pratt

Chapter3: Creating Tables

Section: Chapter Questions

Problem 13RQ

See similar textbooks

Similar questions

Hey experts, please help me out on this :( xx Sample database: For all the implemented tasks, your report or output must include a listing of all PL/SQL statements processed. To achieve that put the following SQL*Plus commands in all your scripts:SPOOL file-nameSET ECHO ONSET FEEDBACK ONSET LINESIZE 100SET PAGESIZE 200SET SERVEROUTPUT ONat the beginning of SQL script andSPOOL OFFat the end of SQL script.PARTSUPP table : i. SELECT p_brand, p_type, p_retailpriceFROM part;ii. SELECT count(*)FROM partWHERE p_brand = 'Brand#18';iii. SELECT l_orderkey, count(*)FROM lineitemWHERE l_orderkey = 1184000GROUP BY l_orderkey;iv. SELECT max(ps_suppkey)FROM partsupp;v. SELECT ps_suppkey, ps_partkey, ps_supplycostFROM partsuppWHERE ps_suppkey = 3699AND ps_partkey = 700;
Create a database in Microsoft access for an online game store inclusive of a data dictionary with at least 5 SQL queries and provide sufficient test data to demonstrate your queries.
This Data in SQL workbench does not work, can someone help me -- Create Company Database CREATE DATABASE Company; -- Use above created Database USE Company; -- Create Customer Table CREATE TABLE Customers ( [Last Name] varchar(255), [First Name] varchar(255), Address varchar(255), City varchar(255), State varchar(100), ZIP int, Tel varchar(100) ); -- Insert data into Customers Table INSERT INTO Customers VALUES ('Smith','Alex','2 South ST','Newark','NJ',07104,'9174251243'), ('Boden','Paul','21 North St','Bergen','NJ',07047,'9083421987'), ('Price','Mary','Apt 3, 11th Ave','NY','NY',10074,'2128137658'), ('Burton','Jane','7 Maple Ave','Tampa','FL',33605,'8132341956'), ('Wang','Jeff','20 Northern BLVD','LA','CA',90006,'2134314356'); -- Create Products Table CREATE TABLE Products ( [Product Name] varchar(255), Category varchar(255), Price float, Quantity int, Received date ); -- Insert data into Products Table INSERT INTO Products VALUES ('3D…
Hey experts, please help me out on this :( xx Sample database: For all the implemented tasks, your report or output must include a listing of all PL/SQL statements processed. To achieve that put the following SQL*Plus commands in all your scripts:SPOOL file-nameSET ECHO ONSET FEEDBACK ONSET LINESIZE 100SET PAGESIZE 200SET SERVEROUTPUT ONat the beginning of SQL script andSPOOL OFFat the end of SQL script.
9.Here is ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'show database CREATE DATABASE [Da]USE PETSTORE' at line 3mysql> use petstoreERROR 1049 (42000): Unknown database 'petstore'mysql> create database [da] -> use petstore -> -> CREATE TABLE USERS (user_id VARCHAR(30), password -> VARCHAR(30), first_name VARCHAR(50), last_name VARCHAR(50));ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '[da] ========== whats the wrong with this work , what code is correct when i ma trying to make a new table and a new databse in this mysql commend line ?.
plz answer correctly!!! oracle pl/sql!! btw plz don't steal other answers from the internet because those answers are false if u know the pl/sql do the answer code without any plagiarism so...cuz 1 stolen code means 1 dislike and no money oke?
Database Question this is a review question The SQL statements that answer these questions. please keep the answer simple will give thumbs up thank you :)! INSERT STATEMENT LINK below https://drive.google.com/file/d/1qHCkrods5K2V1syyS5IG6-Eb_3QQmud7/view?usp=sharing Table.SQL below -- MySQL Script generated by MySQL Workbench-- Sun Feb 21 00:00:31 2021-- Model: New Model Version: 1.0-- MySQL Workbench Forward Engineering SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0;SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0;SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='ONLY_FULL_GROUP_BY,STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,NO_ENGINE_SUBSTITUTION'; -- ------------------------------------------------------- Schema mydb-- ----------------------------------------------------- -- ------------------------------------------------------- Table state-- -----------------------------------------------------CREATE TABLE IF NOT EXISTS state…
Task 5: The InstantRide User Satisfaction team are looking forward to creating discounts for the users. However, the team suspects that there could be duplicate users in the system with different emails. Check for the users with their names and surnames for potential duplicates. Therefore, you need to JOIN the USERS table with USERS table and compare for equality of USER_FIRST_NAME and USER_LAST_NAME and difference in USER_ID fields. Task: Check for duplicate driver accounts. (SQL Database Test)
Database Question this is review Please keep the answer short The SQL statements that answer these questions. please keep the answer simple will give thumbs up thank you :)! INSERT STATEMENT LINK below https://drive.google.com/file/d/1qHCkrods5K2V1syyS5IG6-Eb_3QQmud7/view?usp=sharing Table.SQL below -- MySQL Script generated by MySQL Workbench-- Sun Feb 21 00:00:31 2021-- Model: New Model Version: 1.0-- MySQL Workbench Forward Engineering SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0;SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0;SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='ONLY_FULL_GROUP_BY,STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,NO_ENGINE_SUBSTITUTION'; -- ------------------------------------------------------- Schema mydb-- ----------------------------------------------------- -- ------------------------------------------------------- Table state-- -----------------------------------------------------CREATE TABLE IF…
I am new to databases. Using MySQL I am not certain how to make views relevant to the tables in my database. Can I get help explaining how to several views relative to the tables? Here are the tables I set up in MySQL. Employers: CREATE TABLE Employers ( employer_id INT NOT NULL PRIMARY KEY, company_name VARCHAR(50) NOT NULL, company_street VARCHAR(55) NOT NULL, company_city VARCHAR(55) NOT NULL, company_state VRCHAR(2) NOT NULL, company_zip VARCHAR(10) NOT NULL, company_contact VARCHAR(55) ); Customers: CREATE TABLE Customers ( customer_id INT NOT NULL PRIMARY KEY, customer_name VARCHAR(55) NOT NULL, customer_phone VARCHAR(15) NOT NULL, customer_email VARCHAR(40) NOT NULL, customer_education VARCHAR(55) NOT NULL, customer_experience VARCHAR(55) NOT NULL ); Reference: CREATE TABLE Referral ( customer_id INT NOT NULL PRIMARY KEY, referral_first_name VARCHAR(25) NOT NULL, referral_last_name VARCHAR(25) NOT NULL, referral_location VARCHAR(44) NOT NULL, referral_phone VARCHAR(15),…
The screenshot of the Query and the results below is from the question of each number, and saved with the file name: UAS_NIM.docx or UAS_NIM.pdf Create database : - Show the name of the supplier who sells shoes at prices below the average shoe price- Show the name of the customer who bought shoes with odd sizes- Show Customer Name and Average Payment Amount for Customers who make 5transaction more than 1 Jenis_Sepatu: INSERT INTO Jenis_Sepatu values('S-01', 'Sepatu Lari');INSERT INTO Jenis_Sepatu values('S-02', 'Sepatu Basket');INSERT INTO Jenis_Sepatu values('S-03', 'Sepatu Soccer'); Supplier: INSERT INTO SUPPLIER Values('MA', 'PT. MitraAdi', 'Jl. Monginsidi 87');INSERT INTO SUPPLIER Values('SO', 'PT. Shakti Omega', 'Jl. Sudirman 23');INSERT INTO SUPPLIER Values('SS', 'PT. Sport Station', 'Jl. GunungKelud 8'); Merek: INSERT INTO Merek values('AS', 'Adidas','MA');INSERT INTO Merek values('DA', 'Diadora','SS');INSERT INTO Merek values('PA', 'Puma','SO');INSERT INTO Merek…
Given the following SQL query: Student (sid, name, age, address) Book (bid, title, author) Checkout (sid, bid, date) SELECT S.name FROM Student S, Book B, Checkout C WHERE S.sid = C.sid AND B.bid = C.bid AND B.author = ’Olden Fames’ AND S.age > 12 AND S.age < 20 Write relational algebra query for the above SQL query. Using a drawing tool such as Visio or others (ex: https://www.draw.io/ is a free one) to draw initial relational algebra query trees for the query generated in question 1. Transform the initial query trees created above into a more efficient form (use the heuristic rules and show your steps (.