Please see image and solve part B only Draw the ASMD chart for the following state transition:• If x = 1, control goes from S1 to S2 and then to S3;• If x = 0, control goes from S1 to S3.] What is the value of registers Ro, R1 and R2 after the RTL operations executed in the(a)(b)following order:• So + 1, S1 + 0, Ro + 0, R1 + 20, R2 + 15• R2 + R2 + 1, Rq + R1 + RoIf (S, = 1) then (R1 – R2) else if (S, = 1) then (Ro R2)%3D

Dear Student, Here S0 is given value 1 so, S0 = 1 Similarly , S1 =0, R0 = 0 , R1 = 20, R2 = 15 Now…

(b) ] What is the value of registers Ro, R1 and R2 after the RTL operations executed in the following order: So + 1,S, + 0, Ro – 0, R1 + 20, R2 + 15 • R2 + R2 + 1, R R1 + Ro If (S, = 1) then (R, + R2) else if (S2 = 1) then (Ro R2)

(b) ] What is the value of registers Ro, R1 and R2 after the RTL operations executed in the following order: So + 1,S, + 0, Ro – 0, R1 + 20, R2 + 15 • R2 + R2 + 1, R R1 + Ro If (S, = 1) then (R, + R2) else if (S2 = 1) then (Ro R2)

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter6: System Integration And Performance

Section: Chapter Questions

Problem 19VE

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Concept explainers

LUP Decomposition

LU decomposition stands for Lower-Upper decomposition. LU decomposition is the factorization of the lower triangular matrix and an upper triangular matrix. It is very useful in linear algebra and numerical analysis. A permutation matrix is usually included in the product. Gaussian elimination in a matrix form is known as LU decomposition, When inverting a matrix or evaluating its determinant, this is a crucial step. Tadeusz Banachiewicz, a Polish mathematician, first proposed the LU decomposition in 1938.

Question

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Please see image and solve part B only

Draw the ASMD chart for the following state transition:
• If x = 1, control goes from S1 to S2 and then to S3;
• If x = 0, control goes from S1 to S3.
] What is the value of registers Ro, R1 and R2 after the RTL operations executed in the
(a)
(b)
following order:
• So + 1, S1 + 0, Ro + 0, R1 + 20, R2 + 15
• R2 + R2 + 1, Rq + R1 + Ro
If (S, = 1) then (R1 – R2) else if (S, = 1) then (Ro R2)
%3D

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