B4. Answer all of the following questions: a. List FOUR different design considerations of multiprocessor operating system. b. Considering the following diagram, what would be the contents of MAR, MBR, PC and IR after the fetching of the next instruction.
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B4. Answer all of the following questions:
a. List FOUR different design considerations of multiprocessor
b. Considering the following diagram, what would be the contents of MAR, MBR, PC and IR after the fetching of the next instruction.
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- A(n) __________ is a storage location implemented in the CPU.Assembly Language x86: (Micro Macro): templet: .386.model flat, stdcall.stack 4096ExitProcess PROTO, dwExitCode: DWORD.data day BYTE 0month BYTE 0year WORD 0 .codemain PROC main ENDPINVOKE ExitProcess, 0END main Question: What bit string repersents April 1, 2024? Examples: Date: 00111 (year) 1100 (month) 10010 (day)00111 = 18, 1100 = 12, 10010 = 30, 1980 + 30 = 2010 = 2010 Dec 18mov ax, 00111110010010b; 2010 Dec 10; 30 12 18 DAY:mov dx, ax and dx, 0000000000011111bmov day, dl (18) ; 00111 Month: mov dx, ax and dx, 00000001111000000b shr dx, 5 ; 000000000000 1100 (12) mov month, dl Year:mov dx, axshr dx, 9 ; 011110and dx, 0000000001111111bmov year, dl (30) 10010instruction is in the first picture please give me only implementation of int L1lookup(u_int32_t address) and int L2lookup(u_int32_t address) cacheSim.h #include<stdlib.h>#include<stdio.h>#define DRAM_SIZE 1048576typedef struct cb_struct {unsigned char data[16]; // One cache block is 16 bytes.u_int32_t tag;u_int32_t timeStamp; /// This is used to determine what to evict. You can update the timestamp using cycles.}cacheBlock;typedef struct access {int readWrite; // 0 for read, 1 for writeu_int32_t address;u_int32_t data; // If this is a read access, value here is 0}cacheAccess;// This is our dummy DRAM. You can initialize this in anyway you want to test.unsigned char * DRAM;cacheBlock L1_cache[2][2]; // Our 2-way, 64 byte cachecacheBlock L2_cache[4][4]; // Our 4-way, 256 byte cache// Trace points to a series of cache accesses.FILE *trace;long cycles;void init_DRAM();// This function print the content of the cache in the following format for an N-way cache with M Sets// Set 0…
- 48. An address in main memory is called a. Physical address b. Logical address c. Memory address d. Word addressAssembly Language x86: (Micro Macro): templet: .386.model flat, stdcall.stack 4096ExitProcess PROTO, dwExitCode: DWORD.data .codemain PROC main ENDPINVOKE ExitProcess, 0END main Question: What are the reults (in decimal) of the following operations? A: 1111001000101111 multiplied by 0000001011010010 (these are signed numbers) B: 01011110110101101010010100101001 devided by 1111111111011010 (these are signed number)(hint: use idiv (signed), div (unsigned) ) Examples: Multiply: mul bx, 10000 mov ax, 355 mul bx, shl edx, 16 mov dx, ax Division:mov eax, 2000000 mov bx, 500mov edx, eax shr edx, 16 div bx,0001 = Load AC from memory 0010 = Store AC to memory 0101 = Add to AC from memory 0011 = Load AC (the accumulator register) from an I/O device 0111 = Store AC to an I/O device With these instructions, a particular I/O device is identified by replacing the 12-bit address portion with a 12-bit device number. Remember that a number ending with a small ‘h’ means the number is a hexadecimal number. What is the hexadecimal string that expresses the following instructions? Load AC from memory location 62h. Add the contents of memory location 451h to AC. Store AC to memory location 8h. Store AC to I/O device number 8h.
- C++ LANGUAGE Dynamic Memory Allocation Practice I Write a program that swaps the values of X and Y with malloc. Output Before swap X:412 Before swap Y: 623 After swap X: 623 After swap Y:·412.MODEL SMALL .STACK 100H .DATA ; The string to be printed STRING DB 'This is a sample string', '$' .CODE MAIN PROC FAR MOV AX,@DATA MOV DS,AX ; call reverse function CALL REVERSE ; load address of the string LEA DX,STRING ; output the string ; loaded in dx MOV AH, 09H INT 21H ; interrupt to exit MOV AH, 4CH INT 21H MAIN ENDP REVERSE PROC ; load the offset of ; the string MOV SI, OFFSET STRING ; count of characters of the; ;string MOV CX, 0H LOOP1: ; compare if this is; ;the last character MOV AX, [SI] CMP AL, '$' JE LABEL1 ; else push it in the; ;stack PUSH [SI] ; increment the pointer; ;and count INC SI INC CX JMP LOOP1 LABEL1: ; again load the starting; ;address of the string MOV SI, OFFSET STRING LOOP2: ;if count not equal to zero CMP CX,0 JE EXIT ; pop the top of…Computer Science This question is about paging-based virtual memory A computer has a virtual-momory space of 250MB (megabytes) The computer has 325) of primary memory. The pige som s-4000 by the address is 1011 0001 0101 1110 0010 1010 0010 a. How many frames can it have? b. Which of the bits in the virtual address correspond to the Page number? c. Which of the bits correspond to the page offset?
- Assembly language programming in MIPS. Use QTSpim to run code. Write a simple Assembly Language program that has a data section declared as follows:.data.byte 12.byte 97.byte 133.byte 82.byte 236 Add the values up, compute the average, and store the result in a memory location.CODE (EMU8086) #START = THERMOMETER.EXE##START = LED_DISPLAY.EXE#.STACK 100H .MODEL SMALL .DATA MSG1 DB 10,13,' WELCOME ', DB 10,13,' CHOOSE TYPE OF FOOD ', DB 10,13,'1.) PIZZA 2.) BAKED MACARONI 3.) FRENCH FRIES', DB 10,13,'ENTER: $' MSG2 DB 10,13,'PLEASE SELECT WHAT WILL BE THE MAX TEMPERATURE', DB 10,13,'1.) 20 DEG', DB 10,13,'2.) 40 DEG', DB 10,13,'3.) 60 DEG', DB 10,13,'4.) 80 DEG', DB 10,13,'5.) 100 DEG', DB 10,13,'6.) 119 DEG', DB 10,13,'ENTER: $' NUM1 DB 20 NUM2 DB 40NUM3 DB 60NUM4 DB 80NUM5 DB 100NUM6 DB 119 TIMEOP1 DB 10,13,'SET THE TIMER', DB 10,13,'ENTER 1: 00:00:50', DB 10,13,'ENTER 2: 00:01:40', DB 10,13,'ENTER 3: 00:02:30', DB 10,13,'ENTER 4: 00:03:20', DB 10,13,'ENTER 5: 00:04:10', DB 10,13,'ENTER: $' A DB 0B DB 0C DB 0D DB 0 OPTIONERROR DB 10,13,'INVALID OPTION $' DONE DB 'DONE','$' RESTARTMENU1 DB 10,13,'PRESS 1 TO GO BACK TO…CODE(EMU8086) #START = THERMOMETER.EXE##START = LED_DISPLAY.EXE#.STACK 100H .MODEL SMALL .DATA MSG1 DB 10,13,' WELCOME ', DB 10,13,' CHOOSE TYPE OF FOOD ', DB 10,13,'1.) PIZZA 2.) BAKED MACARONI 3.) FRENCH FRIES', DB 10,13,'ENTER: $' MSG2 DB 10,13,'PLEASE SELECT WHAT WILL BE THE MAX TEMPERATURE', DB 10,13,'1.) 20 DEG', DB 10,13,'2.) 40 DEG', DB 10,13,'3.) 60 DEG', DB 10,13,'4.) 80 DEG', DB 10,13,'5.) 100 DEG', DB 10,13,'6.) 119 DEG', DB 10,13,'ENTER: $' NUM1 DB 20 NUM2 DB 40NUM3 DB 60NUM4 DB 80NUM5 DB 100NUM6 DB 119 TIMEOP1 DB 10,13,'SET THE TIMER', DB 10,13,'ENTER 1: 00:00:50', DB 10,13,'ENTER 2: 00:01:40', DB 10,13,'ENTER 3: 00:02:30', DB 10,13,'ENTER 4: 00:03:20', DB 10,13,'ENTER 5: 00:04:10', DB 10,13,'ENTER: $' A DB 0B DB 0C DB 0D DB 0 OPTIONERROR DB 10,13,'INVALID OPTION $' DONE DB 'DONE','$' RESTARTMENU1 DB 10,13,'PRESS 1 TO GO BACK TO MAIN…