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BALLISTICS The range of an object (see Figure 5.12) shot at an angle 0 with respect to the waxis and an initial velocity t, is given by R(0) = sin (20) for 0 s0s(neglecting air resistance) Use g 9.9 m/s and an initial velocity of 100 m/s. Show that the maximum range is obtained at 0 = 7/4 by computing and plotting the range for values of O from in increments of 0.05. Repeat your calculations with an initial velocity of 50 m/s, and plot both sets of results on a single graph. 1. State the Problem Calculate the range as a function of the launch angle. 2. Describe the Input and Output Input g= 9.9 m/s 0 = 0 to 7/2, incremented by 0.05 th = 50 m/s and 100 m/s 2/24

BALLISTICS The range of an object (see Figure 5.12) shot at an angle 0 with respect to the waxis and an initial velocity t, is given by R(0) = sin (20) for 0 s0s(neglecting air resistance) Use g 9.9 m/s and an initial velocity of 100 m/s. Show that the maximum range is obtained at 0 = 7/4 by computing and plotting the range for values of O from in increments of 0.05. Repeat your calculations with an initial velocity of 50 m/s, and plot both sets of results on a single graph. 1. State the Problem Calculate the range as a function of the launch angle. 2. Describe the Input and Output Input g= 9.9 m/s 0 = 0 to 7/2, incremented by 0.05 th = 50 m/s and 100 m/s 2/24

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Write/modify MATLAB code and create a properly labeled graph.

Add 2 additional lines to your plot, “Cannon Range”, for v3 = 25 m/s and v4= 75 m/s

BALLISTICS The range of an object (see Figure 5.12) shot at an angle 0 with respect to the xaxis and an initial velocity th is given by R(0) = sin (20) for 0 s0s(neglecting air resistance) Use g= 9.9 m/s and an initial velocity of 100 m/s. Show that the maximum range is obtained at 0 = 7/4 by computing and plotting the range for values of O from in increments of 0.05. Repeat your calculations with an initial velocity of 50 m/s, and plot both sets of results on a single graph. 1. State the Problem Calculate the range as a function of the launch angle. 2. Describe the Input and Output Input g= 9.9 m/s 0 = 0 to 7/2, incremented by 0.05 50 m/s and 100 m/s %3D
Transcribed Image Text:BALLISTICS The range of an object (see Figure 5.12) shot at an angle 0 with respect to the xaxis and an initial velocity th is given by R(0) = sin (20) for 0 s0s(neglecting air resistance) Use g= 9.9 m/s and an initial velocity of 100 m/s. Show that the maximum range is obtained at 0 = 7/4 by computing and plotting the range for values of O from in increments of 0.05. Repeat your calculations with an initial velocity of 50 m/s, and plot both sets of results on a single graph. 1. State the Problem Calculate the range as a function of the launch angle. 2. Describe the Input and Output Input g= 9.9 m/s 0 = 0 to 7/2, incremented by 0.05 50 m/s and 100 m/s %3D
Figure 5.12 The ronge is zero, i the conon is perfecty vertical or perfecty horizontal. Output Range R Present the results as a plot. 3. Develop a Hand Example If the cannon is pointed straight up, we know that the range is zero, and if the cannon is horizontal, the range is also zero (see Figure 5.12). This means that the range must increase with the cannon angle up to some maximum and then decrease. A sample calculation at 45 (/4 radians) shows that - sin (20) %3D 100 sin 9.9 (等) = 1010 m when the initial velocity is 100 m/s
Transcribed Image Text:Figure 5.12 The ronge is zero, i the conon is perfecty vertical or perfecty horizontal. Output Range R Present the results as a plot. 3. Develop a Hand Example If the cannon is pointed straight up, we know that the range is zero, and if the cannon is horizontal, the range is also zero (see Figure 5.12). This means that the range must increase with the cannon angle up to some maximum and then decrease. A sample calculation at 45 (/4 radians) shows that - sin (20) %3D 100 sin 9.9 (等) = 1010 m when the initial velocity is 100 m/s
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