Baseball problem (in honor of Opening Day! #LGM)A baseball diamond is a square with sides of 90 feet. A batter hits the ball and runs toward first basewith a speed of 24 ft/sec.(a) How is his distance from second base changing when he is two-thirds of the way to first base?(b) How is his distance from third base changing at the same moment?Note: Distance is true distance from the player to the base, not the length of his path around the bases.

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Asked Mar 28, 2019
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Baseball problem (in honor of Opening Day! #LGM)
A baseball diamond is a square with sides of 90 feet. A batter hits the ball and runs toward first base
with a speed of 24 ft/sec.
(a) How is his distance from second base changing when he is two-thirds of the way to first base?
(b) How is his distance from third base changing at the same moment?
Note: Distance is true distance from the player to the base, not the length of his path around the bases.
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Baseball problem (in honor of Opening Day! #LGM) A baseball diamond is a square with sides of 90 feet. A batter hits the ball and runs toward first base with a speed of 24 ft/sec. (a) How is his distance from second base changing when he is two-thirds of the way to first base? (b) How is his distance from third base changing at the same moment? Note: Distance is true distance from the player to the base, not the length of his path around the bases.

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Expert Answer

Step 1

To calculate the rates of changes of the given quanitities

Step 2

(a) Consider the corresponding diagram

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Step 3

Let y denote the distance from the second base; Required to find rate of change of y wrt time.=dy/dt. Th...

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Math

Calculus

Derivative