Based on a survey, among adults who regret getting tattoos, 20% say that they were too young when they got their tattoos.  Assume that five adults who regret getting tattoos are randomly selected. Does this scenario follow a binomial distribution? Explain why. Find the probability that none of the selected adults who regret getting tattoos, say that they were too young to get tattoos. Find the probability that exactly one of the selected adults who regret getting tattoos, says that he or she was too young to get tattoos. Find the probability that the number of adults who regret getting tattoos, say that they were too young is none or one. Find the mean of adults who regret getting tattoos.

Q: According to recent estimates by the Insurance Corporation of British Columbia (ICBC), 20 percent of…

A: Given: p=0.20 Let  x~B(n,p)

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A: Let X denote the number of selected adults say that they were too young to get tattoos. Then X…

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A: Let us denote X=the number of businesses that have eliminated jobs. n=sample size=6 p=probability of…

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A: Givena safety engineer claims that 2 in 12 automobiles are due to driver…

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A: Let X be the no. of phone calls. μ=3 per minute X~Poisson3

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A:

Q: A San Diego interviewer has found that one in four people approached will agree to take part in her…

A: Solution: Let X be the random variable that the number of people will agree to an interview. The…

Q: Based on a poll , among adults who regret getting tattoos , 38 % say that they were too young when…

A: given data,p(got their tattoos)=0.38q=1-p=1-0-38=0.62n=10x=No.of adults have tattoos

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A:

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A: Let us denote X=the number of internet users who are careful about personal information when using a…

Q: In a recent​ poll, the Gallup Organization found that 45​% of adult Americans believe that the…

A:

Q: A pharmaceutical company claims that 20% of those taking its new allergy medication will experience…

A: Of the people who take the new allergy medication of the company, p = 20% will experience…

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A:

Q: It is estimated that 70% of households own a riding lawnmower. A sample of 22 households is studied.…

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Q: A recent study of cardiovascular risk factors reported that 30% of adults met criteria for…

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Q: The Nationwide Motel Company has determined that 70 percent of all calls for motel reservations…

A: Solution

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A: Since 62% of the internet user is more careful about personal information when using a public ​Wi-Fi…

Q: A report from the Secretary of Health and Human Services stated that70% of single-vehicle traffic…

A:

Q: It is reported that dark chocolate is beneficial to the heart. Suppose that 52% of people in a…

A: Given

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A:

Q: Based on a​ poll, 69​% of Internet users are more careful about personal information when using a…

A: Given Data Probability of success,p = 0.69 Probability of failure,q=(1- 0.69 )= 0.31…

Q: A reputed school when purchasing large shipments of dry erase markers for all its branches. To do…

A:

Q: The average number of flaws in a 100m optic cable is 2.2. If the number of flaws follows a Poisson…

A: Given Information: The average number of flaws in a 100m optic cable is 2.2 If the number of flaws…

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A: Givenp=0.26n=12Let "x" be the couple having destination…

Q: Based on a​ poll, among adults who regret getting​ tattoos, ​17% say that they were too young when…

A:

Q: A study found that consumers in the 18-24 age group go shopping 6.9 times a month on average. For…

A: Here, X is number of times consumers of age group 18-24 go for shopping. We are given average number…

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A: Given : n = 15 p = 0.30 Let X be the number of cable television subscribers.

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A:

Q: Based on a poll , among adults who regret getting tattoos , 25 % say that they were to0 young when…

A:

Q: Current estimates suggest that 70% of the home-based computers in a foreign country have access to…

A:

Q: According to a 2018 survey, 74 percent of employed young adults expect to bring work on a vacation…

A:

Q: Just before a referendum on a school​ budget, a local newspaper polls 357 voters to predict whether…

A: Given, n = 357 p = 53% = 0.53

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A: p=0.68  _________________________ P(x≥1) = ?

Q: Based on a​ poll, among adults who regret getting​ tattoos, 23% say that they were too young when…

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A: 1.b  From the given information, the probability of the prevalence of the students is 20% There…

Q: Based on a​ poll, 68​% of Internet users are more careful about personal information when using a…

A:

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A: Given: β=3δ=968x=562

Q: G. What is the probability that a randomly selected person from this study did not use the patch to…

A:

Q: In a recent​ poll, the Gallup Organization found that 45​% of adult Americans believe that the…

A: Given Data Probability of success,p = 0.45 Probability of failure,q=(1- 0.45 )= 0.55 total number of…

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A:

Q: If the probability of a machine producing a defective part is 0.8, what is the probability of…

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A: Let X be the people who are illiterate. Let person being illiterate be success, then X follows…

Q: Based on a poll , among adults who regret getting tattoos , 27 % say that they were too young when…

A: Let X be the number of the adults say that they were too young to get tattoos which follows binomial…

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A: P: population praportion=praportion of Americans who are afraid to fly. P=0.10 n=Random sample…

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A: Here, too much screen time follows binomial distribution with n = 8 and p = 0.60.

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A: Let, X be the number of cracks in a 105-km expressway. Here , X has Poisson distribution with mean…

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A: Given that  n=10 , p=33%=0.33 , q=1-p=1-0.33=0.67 X~Binomial(n=10,p=0.33) X= Number of blue box

Q: It is reported that American adolescents spend an average of μ =4 hours per day using smart phone (σ…

A: According to the provided information, μ =4 σ = 2

Types of Bias

Statistics is the study of data collection, organization, analysis, interpretation, and presentation. Statistical bias is a characteristic of a statistical technique or its findings in which the expected value deviates from the actual root quantitative parameter being estimated. According to the actual definition of bias, it refers to the tendency of a statistic to overestimate or underestimate a parameter.