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- Help me solve this problem!: Method Skeletons and a Loop Roundup Practice these steps again and then solve the set of loop problems. These problems are more difficult than those in the previous lesson, so you'll need to take your time and work through each one step-by-step. Here is the link: https://codecheck.it/files/1906092225agosqgnp6wc7mwgcfpf6s4wkyWrite a python program that scans in a large number of tweets from a file, and prints the top 5 hashtags. Approach Parse each word in the file Find a way to isolate the hashtags from the rest of the tweet Compute the frequency of each unique hashtag. Find the top 5 hashtags. Caveats 1. Because this is public dataset, there are many tweets that use special characters that may cause issues during reading in your file. To avoid this, explicitly specify the encoding mode in open when reading in the file. with open('twitter_data.txt', 'r', encoding='utf8') as f: 2. When parsing hashtags be sure to change everything to lowercase. There are cases in the file where two hashtags are the same but differ in case. 3. There is no standard way of sorting a dictionary based on the values. Python gives you access to a sorted function where you can pass in a collection and also specify a comparator which outlines how you want to sort the values. This can be done with a one line lambda function.Stack CreateStack(S) push (S, 10) push (S, 15) push (S, 20) x = top (S) push (S, x + 5) x = pop (S) + top (S) push (S, x – pop (S)) push (S, pop (pop (S))) push (S, x – top (S)) push (S, push(S, x) – top (S)) After executing the given codes above, answer the questions and explain. Thanks
- How do I use webscraping techniques to retrieve https://www.gutenberg.org/files/11/old/alice30.txt? Then update the following code to read and print out the unique words in each chapter with the aid of adictionary and a set. from re import split def main() : # Read the word list and the document. correctly_spelled_words = read_words("words", "") document_words = read_words("alice30.txt", "*END*") # Skip the prefix # Print all words that are in the document but not the word list. misspellings = document_words.difference(correctly_spelled_words) for word in sorted(misspellings) : print(word) def read_words(filename, skip_until) : word_set = set() input_file = open(filename, "r") skip = True for line in input_file : line = line.strip() if not skip : # Use any character other than a-z or A-Z as word delimiters. parts = split("[^a-zA-Z]+", line) # notice this unique split function from the re module for…# The first message in the file was decrypted, its plaintext is: plain_text = 'PICK UP THAT CAN CITIZEN' # create a list of characters of the alphabet alphabet_list = list('ABCDEFGHIJKLMNOPQRSTUVWXYZ') # use list compression to create the alphabet mapping to the integers, starting with 0 alphabet_int_list = [i for i in range(0,26)] # create a list to hold the encrypted message strings encrypted_messages_list = [] # open the file of encrypted messages in read mode, call it encrypted_messages_file with open('encrypted_messages.txt', 'r') as encrypted_messages_file: # readlines() reads all the lines of a file in one go and returns each line as a string element in a list encrypted_messages_list = encrypted_messages_file.readlines() # we use list compression to, for each line in the list, remove the whitespace (i.e. the new line character) # and then store the results in a list encrypted_messages_list = [line.strip() for line in encrypted_messages_list]…Consider you are given a very specialized string with a unique format as: Quiz_(no) # (q.no) : (question statement) $ (option1) , (option 2) , … * (right option number) … \n String starts with Quiz_ (quiz number like 1, 2, … ), then hash #, then question number (like qno_1, qno_2 …), then colon :, then question statement, then dollar $, then options (like option1, option 2 …), then asterisk *, and then right option for the given question statement. If more questions are there for the same quiz, then pattern after hash # is repeated (means every question is separated by # symbole). Each quiz ends with new line (\n), and then new quiz starts with same pattern as before. A sample pattern is given below. You are required to create a program in JAVA, in such a way that if your program receives any string with this pattern (or format) it should provide output as given below. (Hint: Use split, trim method to do the job) String starts with Quiz_ (quiz number like 1, 2, … ), then hash #, then…
- Consider you are given a very specialized string with a unique format as: Quiz_(no) # (q.no) : (question statement) $ (option1) , (option 2) , … * (right option number) … \n String starts with Quiz_ (quiz number like 1, 2, … ), then hash #, then question number (like qno_1, qno_2 …), then colon :, then question statement, then dollar $, then options (like option1, option 2 …), then asterisk *, and then right option for the given question statement. If more questions are there for the same quiz, then pattern after hash # is repeated (means every question is separated by # symbole). Each quiz ends with new line (\n), and then new quiz starts with same pattern as before. A sample pattern is given below. Quiz_1# qno_1: What comes next to First $first, second, third, fourth *2 # qno_2: What comes before second $first, second, third, fourth, fifth *1 \nQuiz_2# qno_1: What is liquid $water, bread, smoke *1 # qno_3: What is hot $ice-cream, candies, spices *3 You are required to create a…Write a program that reads a text file and creates an alphabetical index of words and in which lines of this original example. The file name is given as an argument to main (). Ignore the small-capital (all lowercase: k,l,p) and punctuation. Solve with ternary tree using the TST.java class (https://algs4.cs.princeton.edu/52trie/TST.java.html). An execution snapshot is then given. For the file: It was the best of times, it was the worst of times, it was the age of wisdom, it was the age of foolishness It will appear Index of file: exercise.txt age 3-4 best 1 foolishness 4 it 1-2-3-4 of 1-2-3-4 the 1-2-3-4 times 1-2 was 1-2-3-4 wisdom 3 worst 2In python >>> build_csv_string([["Sam", "Lab 01", 5.4]]) 'name,assignment,grade\nSam,Lab 01,5.4' >>> build_csv_string([["Sam", "Lab 01", 5.4], ["Zoe"]]) 'name,assignment,grade\nSam,Lab 01,5.4\nZoe,N/A,0' >>> build_csv_string([["Sam", "Lab 01", 5.4], ["Zoe"], ["Amanda", "Quiz 04", 100]]) 'name,assignment,grade\nSam,Lab 01,5.4\nZoe,N/A,0\nAmanda,Quiz 04,100'
- Implement a blog server in C 1. Implement get of all posts (GET /posts), and individual post (GET /post/1) 2. Implement creation of post (POST /posts). Allow the user to enter their name, but check that they are a valid user in db. Do error checking! The user should not specify the post id; that should come from the database. 3. Write three html files to test this; serve them with the blog server: index.html shows the list of posts with a link to each. post.html shows a post. publish.html allows the creation of a new post. Link these together as a user would expect!This is the implementation of the Caesar cipher (Section5.3 in the textbook), which we discussed in class. Caesar cipher is a simple approach toencoding messages by shifting each letter in a message along the alphabet by aconstant amount.Your code will be similar to Listing 5.1, but you must use CircularArrayQueue.javainstead of the Java API queue. //5.1 import java.util.*;public class Codes { public static void main(String[] args) { int[] key = {5, 12, -3, 8, -9, 4, 10}; Integer keyValue; String encoded = "", decoded = ""; String message = "All programmer are playwrights and all "+"computers are lausy actors."; Queue<Integer> encodingQueue = new LinkedList<Integer>(); Queue<Integer> decodingQueue = new LinkedList<Integer>(); for (int scan=0; scan < key.length; scan++) { encodingQueue.add(key[scan]); decodingQueue.add(key[scan]); } for (int scan=0; scan < message.length();…The acclaimed _NumPy_ library, that `Simpy` is inspired by, allows you to use the subscription operator not just to select individual items, but also to filter with a mask. It adds a second usage to the operator, just like you have had two uses of many of the operators above, such as adding two `Simpy`s or a `Simpy` and a `float`. The big idea of the second usage of subscription notation is that if instead of giving an `int` inside the subscription brackets you give a `list[bool]`, the expression will return a new `Simpy` object containing only the _masked_, or filtered, `values`. For example: ~~~python a = Simpy([1.0, 2.0, 3.0, 4.0, 2.0, 1.0]) mask = a > 2.0 print(mask) # Output: [False, False, True, True, False, False] b = a[mask] print(b) # Output: Simpy([3.0, 4.0]) ~~~ The above example did not need to establish a separate variable named `mask`, it only did so to make it obvious what the `mask` values were. More conventionally, the above example would be written in a…