Be Pa binary predicate on a domain Dany. Consider the following sentences in predicate logic: PR = Vr (P(x, x)) Ps = VrVy (P(x,y) → P(y, x)) Or = VrVyVz (P(x, y) ^ P(y, z) → P(r, z)) oy = VrVyVz (P(r, y) ^ P(r, z) → P(y, z)) ex = VrVyVz (P(y, x) ^ P(z, x) → P(y, 2)) PE = PRAPS A OT Show that: a) PR A Yv = PE b) PR AYx = PE

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter5: Rings, Integral Domains, And Fields
Section5.3: The Field Of Quotients Of An Integral Domain
Problem 6E
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Be Pa binary predicate on a domain D any. Consider the following sentences in predicate logic:
PR = VI (P(r,1))
Ps = VrVy (P(r, y) → P(y, x))
Or = VrVyVz (P(r, y) ^ P(y, z) → P(r, z))
oy = VrVyVz (P(r, y) ^ P(r, 2) → P(y, z))
ex = VrVyVz (P(y, x) ^ P(z, x) → P(y, 2))
Show that:
a) PR A ev = PE
b) YR AYx = PE
Transcribed Image Text:Be Pa binary predicate on a domain D any. Consider the following sentences in predicate logic: PR = VI (P(r,1)) Ps = VrVy (P(r, y) → P(y, x)) Or = VrVyVz (P(r, y) ^ P(y, z) → P(r, z)) oy = VrVyVz (P(r, y) ^ P(r, 2) → P(y, z)) ex = VrVyVz (P(y, x) ^ P(z, x) → P(y, 2)) Show that: a) PR A ev = PE b) YR AYx = PE
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