because 0< < 1, the sequence converges monotonically to zero. 10.2.28 -0.003 < 1, so the sequence converges to zero. 10.2.29 Because |0.5| <1 and |0.75 < 1, the sequence converges to 0+3.0=0. en + " (:)") 10.2.30 lim lim (1+ which doesn't exist, because =1+ lim >1. > 1. 1. en n-00

Intermediate Algebra
19th Edition
ISBN:9780998625720
Author:Lynn Marecek
Publisher:Lynn Marecek
Chapter12: Sequences, Series And Binomial Theorem
Section12.1: Sequences
Problem 74E: Which terms of the sequence are negative when the nth term of the sequence is an=(1)n(n+2)?
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What test are we using for # 30? The original problem is written on scrap paper in pencil

Irk1 conu
dive
CO
2.
< 1, the sequence converges monotonically to zero.
because 0 <
Irl21
10.2.28 |-0.003< 1, so the sequence converges to zero.
10.2.29 Because |0.5 < 1 and |0.75< 1, the sequence converges to 0+3 · 0 = 0.
en + T"
(1+ (*)") =1
T
n
10.2.30 lim
lim (1+ () ) = 1+ lim ()7 which doesn't exist, because
n
> 1.
n 00
en
e
e
e
Transcribed Image Text:Irk1 conu dive CO 2. < 1, the sequence converges monotonically to zero. because 0 < Irl21 10.2.28 |-0.003< 1, so the sequence converges to zero. 10.2.29 Because |0.5 < 1 and |0.75< 1, the sequence converges to 0+3 · 0 = 0. en + T" (1+ (*)") =1 T n 10.2.30 lim lim (1+ () ) = 1+ lim ()7 which doesn't exist, because n > 1. n 00 en e e e
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