Below is a transit and tape survey notes of a lot. 1.) Compute the angular error of deflection angle. 2.) Compute the linear error of closure of the traverse. 3.) Compute the area in square meters. Deflection Station Angle Line Bearing Distance 1 55°30' R 1-2 10°00' E 650 99 30' R 2-3 895 3 44°00' R 3-4 315 4 92°00' R 4-5 875 68 55' R 5-1 410 2]

Below is a transit and tape survey notes of a lot. 1.) Compute the angular error of deflection angle. 2.) Compute the linear error of closure of the traverse. 3.) Compute the area in square meters. Deflection Station Angle Line Bearing Distance 1 55°30' R 1-2 10°00' E 650 99 30' R 2-3 895 3 44°00' R 3-4 315 4 92°00' R 4-5 875 68 55' R 5-1 410 2]

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

ABCDA is a clockwise closed traverse.Given: XA=YA=200.00 m, Azimuth ??? = 290, the angle ??? = 270 (angles in degrees) The data is as followsa. Draw the figure.b. Adjust the angles.c. Compute azimuths of all sides.d. Adjust the traverse and compute coordinates of the traverse station.
1. A triangular piece of land ABC (clockwise) has the following directions in azimuth fom South. AB = 225o23’, BC = 325o20’, CA = 100o10’ Compute the interior angles. 2. An open traverse ABCDE has following azimuth from South: AB = 250o30’ BC = 280o20’ CD= 210o45’ DE = 150o50’ Required: Deflection angles at points B,C, and D. Draw the figure properly.
Given the closed traverse data. Lines Bearing Distance AB N20o E 20.35 BC N68oE 18.75 CD S22oE 21.30 DE S40oW 13.35 EF S62oW 9.23 FA Compute the following. Compute the bearing and distance of line FA Compute the area of the given traverse
fundamentals of surveying. ANGLE TO THE RIGHT TRAVERSE. A five-sided closed traverse proceeds in a clockwise direction and the angle to the right at each station were observed as follows: A = 270° 45’, B = 268° 43’, C = 203° 22’, D = 256° 20’, and E = 260° 25’. Determine the error in the sum of the angles. Adjust the angular values observed on the assumption that the error is the same for each angle. Tabulate all observed and adjusted values accordingly.
In a given closed traverse the sum of the south latitudes exceeds the sum of the north latitudes by 4.55 m and the sum of the east departures by exceeds the sum of the west departures by 2.83 m, determine the linear error of closure, bearing of the side of error, and the precision of the survey performe
Can differential leveling be combined with trigonometric leveling in an adjustment? Explain how you would handle their relative qualities in a least squares analysis? Explain properly.
A transit with a stadia constant equal to 0.30 is used to determine the horizontal distance betweeen points B and C, with a stadia intercept reading of 1.75 m, the distance BC is equal to 185.87m. Using the same instrument, it was used to determine the difference in elevation between B and D having a stadia intercept reading of 2.42 m at D at a vertical angle of (+) 6-30-00. Compute the difference in elevation of B and D. a.26.91 b. 28.90 c. 22.78 d. 23.78
The following data were obtained by stadia observation: vertical angle Ѳ = +9degree25min, upper stadia hair and lower stadia hair readings are 2.352 m and 0.995 m, respectively. The stadia interval factor is known to be 99.0 and C = 0.381 m. The height of the instrument above the instrument station (point A) is 1.496 m and the rod reading is taken at 1.589 m. Elevation of point A is 776.545. determine the inclined distance AB? In Problem 1 determine the horizontal distance In Problem 1 determine the vertical distance In Problem 1, Determine the elevation of B
A trigonometric leveling conducted by Montragon Surveying Company, the two points A and B of a certain rough terrain are each distance 3000m from a third point C from which the measure vertical angles to A is +5°30’ and to B is 6°30’. Elevation at C is known to be 342.60m above sea level point C is in between A and B. Considering the effects of curvature and refraction. a.) Compute the difference in elevation between A and B. b.) Compute the difference in elevation between B and C. c.) Compute the elevation of A.
PROBLEM 1 Given the following interior angles (angles-to-the-right) of a five-sided closedpolygon traverse and if the azimuth of side AB is fixed at 74°31'17", determine the adjusted azimuth of line EA.A =105°13'14"; B = 92°36'06"; C = 67°15'22"; D = 217°24'30"; E = 57°30"38". (Note: line BC bears NW.) ANSWER HERE IS: Azimuth EA=149.300278 PROBLEM 2 Compute the linear misclosure for the traverse of Problem 1 if the lengths of the sides (in feet) are as follows: AB = 2157.34; BC =1722.58;CD =1318.15; DE =1536.06; and EA =1785.58. (Note: Assume units of feet for all distances.)Round off your answer to three decimal places. No need to include the unit. ANSWER HERE IS: 0.065 NEEDED TO ANSWER im confuse Using the compass (Bowditch) rule, adjust the departures and latitudes of the traverse in Problem 1 considering the length of Problem 2. If the coordinates of station A are X = 20,000 ft and Y = 15,000 ft, calculate x coordinates of course DE.
A closed traversed has the following data. LINE DISTANCE BEARING AB 185.33 N 43 E BC 258.28 S 67 E CD ? S 38 W DE ? S 81 W EA 150.87 N 27 W The summation of the latitude and departure of the traverse are -26 and 55, respectively. Using COMPASS RULE, determine the follwowing:(Round off into four decimal places)DETERMINE THE CORRECTED LATITUDE OF THE LINE CD.
Compute the closure error in closed-polygon traverse if you know the relative precision (1/12000) and the total length of the traverse is 1059.671 m