(b)(i) Use Gaussian Elimination and back substitution to solve the following system of linear equations. 1 + #3 + 24 = -2.21 2 2.x2 + √5.23 21 + = 2-3 4.3 √2.x2 + x1 = x2 = #3 II X4= 10-24 -50 0

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