Binary Search algorithm has an element given in sequential arrays. We have seen that at the O (logN) time complexity. We saw in the lesson The algorithm determines whether a given element exists in sequential but non-element repetitive arrays and returns the index if the element exists in the array, and -1 if it does not. This time, again In an array that is given sequentially, but can contain element repeats, there is a given element and the lowest value eye (if any) containing that element. Since we assume that there may be the same valued elements in the eye, one of them has the index we want to know), otherwise we can use the algorithm of the binary search function that returns -1 as pseudocode.

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