BR main number: .EQUATE 6 j: .EQUATE 4 amount: .EQUATE 2 result: .EQUATE O main: SUBSP 8, i DECI number, s LDWA 0, i STWA result, s LDWA 1, i STWA j, s for: CPWA number, s BRGT endFor DECI amount, s LDWA amount, s
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- Find output of following code. If there is an error in code, make it correct and write the output mov ax, 20 mov bx, 0 subtraction: sub ax, [num1+bx] add bx, 2 cmp bx, 6 jne subtraction num1: dw 2, 1, 4, 1, 2Image shows the question, below is an example output: Latitude: 23 [FAILED] Calculated CRC: 3 Expected CRC: 6 1011100010110000--------00001000 0000100000001011--------00000011 Longitude: 80 [FAILED] Calculated CRC: 5 Expected CRC: 4 10100000001011000000----------0001000000 00010000000001011000----------0000011000 00000110000000010110----------0000001110 00000011100000001011----------0000000101 Elevation: 13548 [OK] 1101001110110000010110000000000000-----------------01100011101100000 0110001110110000001011000000000000-----------------00111011101100000 0011101110110000000101100000000000-----------------00010111101100000 0001011110110000000010110000000000-----------------00000001101100000 0000000110110000000000001011000000-----------------00000000110100000 0000000011010000000000000101100000-----------------00000000011000000 0000000001100000000000000010110000-----------------00000000001110000 0000000000111000000000000001011000-----------------00000000000101000…Please fix the code, and make it give the exact output at least please
- This is the updated code that I have: .data .globl main .textmain: # compute the next state of the LFSR for each input state li $a0, 0x00000001 jal lfsr_next_state move $t0, $v0 li $a0, 0xdeadbeef jal lfsr_next_state move $t1, $v0 li $a0, 0x200214c8 jal lfsr_next_state move $t2, $v0 li $a0, 0x00000000 jal lfsr_next_state move $t3, $v0 # print the output states move $a0, $t0 li $v0, 1 syscall move $a0, $t1 li $v0, 1 syscall move $a0, $t2 li $v0, 1 syscall move $a0, $t3 li $v0, 1 syscall # exit the program li $v0, 10 syscall # Function to compute the next state of an LFSR# Input parameter: $a0 = current state# Output: $v0 = next statelfsr_next_state: # Initialize upper mask with 0x7fff and lower mask with 0x8000 lui $t0, 0x7fff ori $t0, $t0,…I am still getting the wrong output with the updated code with the fix. This is the updated coded that you provided: .data .globl main .textmain: # compute the next state of the LFSR for each input state li $a0, 0x00000001 jal lfsr_next_state move $t0, $v0 li $a0, 0xdeadbeef jal lfsr_next_state move $t1, $v0 li $a0, 0x200214c8 jal lfsr_next_state move $t2, $v0 li $a0, 0x00000000 jal lfsr_next_state move $t3, $v0 # print the output states li $v0, 1 move $a0, $t0 syscall li $v0, 1 move $a0, $t1 syscall li $v0, 1 move $a0, $t2 syscall li $v0, 1 move $a0, $t3 syscall # exit the program li $v0, 10 syscall # Function to compute the next state of an LFSR# Input parameter: $a0 = current state# Output: $v0 = next statelfsr_next_state: # Initialize upper mask with…use ibm is400 series to answer the following question (the output should shown in screenshot) 1 - develop a new Library called MnnLIB1 (NN is your student login id number) using the command CRTLIB 2 - develop a new Jobq MnnJOBQ1 and Outq MnnOUTQ1 in the Library MnnLIB1 using the command crtjobq and crtoutq 3 - Grant *PUBLIC *USE Authority to your MnnLIB1 library using the command wrkobj MnnLIB1 and then option 2 4 - Submit 3 jobs using sbmjob in your MnnJOBQ1, these jobs will not run, since they are not attached to any sub-system. Check it out by using wrkjobq command 5 - Change the 3 jobs submitted in step #4 to run in sub-system QINTER and change the out to MnnOUTQ1. These jobs will run, and the results will be in MnnOUTQ1. Check it out by using wrkoutq command 6 - develop a new Source File called MnnSRC in your library MnnLIB1 using command crtsrcpf 7 - develop a new Save File called MnnSAVF in your library MnnLIB1 using command crtsavf 8 - Run DSPJOBLOG command and save the…
- Could you please fix the yellow highlighted errors in attachedment? The expected output is not correct.QUESTION ATTACHED KINDLY SEE AND MATCH INPUT-OUTPUT AS IT IS. ALSO, USE THE BELOW TEMPLATES WHILE MAKING A SOLUTION ---------TEMPLATES------------ main.cpp #include <iostream>#include <sstream>#include "Donor.cpp"using namespace std;int main(){//Fill your code heretry{//Fill your code here}catch(const char* c){//Fill your code here}return 0;} Donor.cpp #include <iostream>#include <sstream>using namespace std;class Donor{protected:string name;int age;int weight;string bloodGroup;public:Donor(){}Donor(string name, int age, int weight,string bloodGroup) {this->name = name;this->age = age;this->weight = weight;this->bloodGroup = bloodGroup;}bool validateDonor(Donor donor){//Fill your code here }};Using the following snippet of code, introduce the walrus operator to re-write the code using less lines. Aim for half of the lines used while producing and preserving the same output that this code provides
- Trace the following Code and then print the output. msg db 'hello world$' newline db 10,13,'$' buffer db 10 dup mov ah,9 mov dx,offset msg int 21h ;new line mov ah,9 mov dx, offset newline int 21h ;enter a string from the keyboard lea dx,buffer mov ah,0ah int 21h ;new line mov ah,9 mov dx,offset newline int 21h ;adding the $ symbol at the end of the string mov bx,0 mov bl,buffer[1] mov buffer[bx+2],'$' mov ah,9 mov dx,offset buffer+2 int 21hCan you exlplain with comments following data .data prompt byte1 "Input number1:-" mynumber1 byte1 10 prompt byte2 "Input number2:-" mynumber2 byte2 10 .code main PROC cmp mynumber1 , mynumber2 jl Less move Word [temp] , mynumber2 jump both: Less: move Word [temp] , mynumber1 Both: prompt demo "Input Newnumber1:-" demo1 demo10 cmp demo1, temp jl Less move Word [temp] , temp jump both: Less: move Word [temp] , demo1 And the cycle continues(This is for Cengage Mindtap, highly recommend using this. If not available, use devc++ version 5.11 but Cengage will be more precise sometimes.) Instructions Write a program that takes, as input, five numbers and outputs the mean (average) and standard deviation of the numbers. If the numbers are x₁, x₂, x₃, x₄, and x₅, then the mean is: x = (x₁+ x₂+ x₃+ x₄+x₅)/5 and the standard deviation is: s = √(((x₁-x)²+(x₂-x)²+(x₃-x)²+(x₄-x)²+(x₅-x)²)/5) Your program must contain at least the following functions: a function that calculates and returns the mean and a function that calculates the standard deviation. Format your output with setprecision(2) to ensure the proper number of decimals for testing!