by CodeChum Admin Remember the game of FizzBuzz from the last time? Well, I thought of some changes in the game, and also with the help of loops as well. Firstly, you'll be asking for a random integer and then loop from 1 until that integer. Then, implement these conditions in the game: • print "Fizz" if the number is divisible by 3 • print "Buzz" if the number is divisible by 5 • print "FizzBuzz" if the number is divisible by both 3 and 5 • print the number itself if none of the above conditions are met Input 1. An integer Output The first line will contain a message prompt to input the integer. The succeeding lines will contain either a string or an integer. Enter n: 15 2 Fizz Buzz Fizz 7 1 Fizz Buzz 1 2 3 9 10 =======✿✿¤¤¤×¤*** 5 6 7 int n1 = 0; 11 12 13 15 16 17 18 19 20 24 25 27 #include 28 main int n; printf("Enter n: "); scanf("%d,&n"); while (n-1):{ if (n%30 && X5--0); { printf("fizzbuzz"); } else if("%3--0"); { printf("fizz"); } else if("%5--0"); printf("buzz"); { main.c:20:5: error: 'else' without a previous 14" 20 | else if(""); Expected Output Enter n: 15 1 2 Fizz 4 Buzz Fizz 7 8 Fizz BUZI 11 Fizz 13 14 FizzBuzz Test Case 2 Ⓒ Test Case 3

by CodeChum Admin Remember the game of FizzBuzz from the last time? Well, I thought of some changes in the game, and also with the help of loops as well. Firstly, you'll be asking for a random integer and then loop from 1 until that integer. Then, implement these conditions in the game: • print "Fizz" if the number is divisible by 3 • print "Buzz" if the number is divisible by 5 • print "FizzBuzz" if the number is divisible by both 3 and 5 • print the number itself if none of the above conditions are met Input 1. An integer Output The first line will contain a message prompt to input the integer. The succeeding lines will contain either a string or an integer. Enter n: 15 2 Fizz Buzz Fizz 7 1 Fizz Buzz 1 2 3 9 10 =======✿✿¤¤¤×¤*** 5 6 7 int n1 = 0; 11 12 13 15 16 17 18 19 20 24 25 27 #include 28 main int n; printf("Enter n: "); scanf("%d,&n"); while (n-1):{ if (n%30 && X5--0); { printf("fizzbuzz"); } else if("%3--0"); { printf("fizz"); } else if("%5--0"); printf("buzz"); { main.c:20:5: error: 'else' without a previous 14" 20 | else if(""); Expected Output Enter n: 15 1 2 Fizz 4 Buzz Fizz 7 8 Fizz BUZI 11 Fizz 13 14 FizzBuzz Test Case 2 Ⓒ Test Case 3

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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This is the code that needs to be updated: .ORIG x3000 LD R0, NUM LD R1, DEN JSR GCD ADD R4, R1, #0 ADD R1, R2, #0 JSR DIVIDE ST R2, NUM ADD R0, R4, #0 JSR DIVIDE ST R2, DEN HALT; you can try other values for NUM and DEN by replacing these values in the simulatorNUM .FILL #10 DEN .FILL #3 ; Divide R0 by R1, putting quotient in R2 and remainder in R3DIVIDE ; Euclid's algorithm for GCD of R0 and R1, result in R2GCD .END
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Add a method called multiplesOfFive to the Exercise class. The method must have a void return type and take a single int parameter called limit. In the body of the method, write a while loop that prints out all multiples of 5 between 10 and limit (inclusive) on a single line. For instance, if the value of limit were 15 then the method will print: 10 15 You can use the printEvenNumbers method that is already in the Exercise class as an example to help you work out how to complete this method. In the main method of the Main class, add a call on the Exercise object to your multiplesOfFive method that prints the multiples of 5 between 10 and 25. Add a method called sum to the Exercise class. The method must have a void return type and take no parameters. In the body of the method, write a while loop to sum the values 1 to 10 and print the sum once the loop has finished. In the main method of the Main class, add a call on the Exercise object to your sum method. Check that it prints: 55 Add…
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Can you write a new code in Java language with the values I sent you, just like this output? There are two files named group1.txt and group2.txt that contain course information and grades of each student for each class. I will calculate each course average for each group and show in simple bar graph. Use "*" and "#"characters for group1 and group2, respectively. I will see the number -999 at the end of each line in the input files. This value is used for line termination and you can use it to verify that you have arrived at the end of the line. The averages of each group should also be calculated and printed at the end of the file. Group 1: CSC 80 100 70 80 72 90 89 100 83 70 90 73 85 90 -999 ENG 80 90 80 94 90 74 78 63 83 80 90 -999 HIS 90 70 80 70 90 50 89 83 90 68 90 60 80 -999 MTH 74 80 75 89 90 73 90 82 74 90 84 100 90 79 -999 PHY 100 83 93 80 63 78 88 89 75 -999 Group 2: CSC 90 75 90 75 80 89 100 60 80 70 80 -999 ENG 80 80 70 68 70 78 80 90 90 76 -999 HIS 100 80 80 70 90 76 88…
in java String inputWord is read from input. Write a while loop that iterates until inputWord is equal to "Finale". In each iteration of the loop: Read integer clothingNumber from input. If clothingNumber is less than 30, output the value of inputWord, followed by ": low on stock" and a newline. Otherwise, output the value of inputWord, followed by ": well stocked" and a newline. Read string inputWord from input. Click here for example 1 2 3 4 5 6 7 8 9 10 11 12 13 14 import java.util.Scanner; public class PairedDataProcessing { publicstaticvoidmain(String[] args) { Scannerscnr=newScanner(System.in); StringinputWord; intclothingNumber; inputWord=scnr.next(); /* Your code goes here */ } }
for the class ArrayAverage write a code that calculates the average of the listed numbers with a double result for the class ArrayAverageTester write a for each loop and print out the result
On a piano, a key has a frequency, say f0. Each higher key (black or white) has a frequency of f0 * rn, where n is the distance (number of keys) from that key, and r is 2(1/12). Given an initial key frequency, output that frequency and the next 4 higher key frequencies. NOTE: You must use a for loop. Output each floating-point value with two digits after the decimal point, which can be achieved by executingcout << fixed << setprecision(2); once before all other cout statements. Ex: If the input is: 440.0 (which is the A key near the middle of a piano keyboard), the output is: 440.00 466.16 493.88 523.25 554.37 Note: Use one statement to compute r = 2(1/12) using the pow function (remember to include the cmath library). Then use that r in subsequent statements that use the formula fn = f0 * rn with n being 1, 2, 3, and finally 4. Note: setprecision requires you to include the iomanip header file Write in C++.Please and thank you.