ncSqgHuCpmyhO2nvmCPguu9empi-50FsWnfm42xQ/formResponseQuestion*By shifting the summation index of the following added series+00п(п - 1)С, х" - 4п(п — 1)С, х"-2+3nC,x" +C,x" = 0n=2we get:E[(k – 2)(k – 3)C2C, - Co + 6C,x +£t(k + 1)(k – 1)G,+(k + 2)(k + 1)C+z]x* = 0+(k + 2)(k + 1)Cr+2]x* = 0O This optionThis option(C, - 8C;) + (4C, - 24C,)x2C, + Co + E(1 – 2k)Cx+EI(k + 1)°C – 4(k + 2)(k+1)Gr+z]r* = 0+(k + 2)(k + 1)Ck+2]xk = 0O This optionThis option

Given that ∑n=2∞nn−1Cnxn−4∑n=2∞nn−1Cnxn−2+3∑n=1∞nCnxn+∑n=0∞Cnxn=0. Now, we only need to shift the…

By shifting the summation index of the following added series +00 +00 En(n-1),x"-4[n(n-1)C₁x"-2 +3 + [₁x²-0 n=2 n=2 n=1 we get: Eko[(k-2) (k-3)Ck 2C₂-Co +6C₂x +[(k+ 1)(k-1) Ck +(k+ 2)(k+1) Ck+2]x* = 0 +(k+2) (k+1)C+2]x* = 0 This option This option (Co-8C₂)+(4C₂-24C₂)x 2C₂+ Co + 1[(1 - 2k) Ck +(k+ 2) (k+1) Ck+2]xk = 0 +(k+ 1)²C₂-4(k+2)(k+1)C+]x* = 0 This option This option

By shifting the summation index of the following added series +00 +00 En(n-1),x"-4[n(n-1)C₁x"-2 +3 + [₁x²-0 n=2 n=2 n=1 we get: Eko[(k-2) (k-3)Ck 2C₂-Co +6C₂x +[(k+ 1)(k-1) Ck +(k+ 2)(k+1) Ck+2]x* = 0 +(k+2) (k+1)C+2]x* = 0 This option This option (Co-8C₂)+(4C₂-24C₂)x 2C₂+ Co + 1[(1 - 2k) Ck +(k+ 2) (k+1) Ck+2]xk = 0 +(k+ 1)²C₂-4(k+2)(k+1)C+]x* = 0 This option This option

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter10: Sequences, Series, And Probability

Section10.2: Arithmetic Sequences

Problem 68E

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