By shifting the summation index of the following added series +00 Σ +00 +00 > n(n-1)Cx" - 4 n(n-1)C,x-2+3 nC,x" + Cx" 0 %3D n=2 n=2 we get:

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.2: Arithmetic Sequences
Problem 40E
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E Reading list
By shifting the summation index of the following added series
+00
+00
> n(n-1)C,x" - 4
n(n – 1)G,x"-2 + 3 nCx" +20
Cx" =0
n=2
n=2
we get:
2C, + Co +E[(1– 2k)C
(C,-8C) + (4C 24C,)x
+(k + 2)(k + 1)CK+2]x* =0
+E(k +1)°C- 4(k + 2)(k + 1)G]x* =0
This option
O This option
EO[[k – 2)(k - 3)C
+(k +2)(k + 1)Ck+2]x* = 0
Transcribed Image Text:E Reading list By shifting the summation index of the following added series +00 +00 > n(n-1)C,x" - 4 n(n – 1)G,x"-2 + 3 nCx" +20 Cx" =0 n=2 n=2 we get: 2C, + Co +E[(1– 2k)C (C,-8C) + (4C 24C,)x +(k + 2)(k + 1)CK+2]x* =0 +E(k +1)°C- 4(k + 2)(k + 1)G]x* =0 This option O This option EO[[k – 2)(k - 3)C +(k +2)(k + 1)Ck+2]x* = 0
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