By shifting the summation index of the following added three series Σ n(n-1)₂x + [n n(n-1)C₂x-²-4n1"+ WW2 192 we get: Σ[(k-2)(k-3)Ck +(k+2)(k+1)C+2]x* = 0 O This option (CBC₂)+(4C-24₂) +0+1G-4(+2)+1²-0 MWI Mi O This option 60₁x²-0 2C₁-C₂ +6C₂x+2+1)(k-1₂ +k+ 2)(k+1)x-0 2C₂+Co+(1-2k)C +(k+ 2) (k+1)C.]x* = 0

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.3: Geometric Sequences
Problem 44E
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By shifting the summation index of the following added three series
n(n – 1)C, x" +
n(n – 1)C,x*-3 –) 4nC, 1" +
6C,x"-0
TOO_BL
we get:
E[(k - 2)(k - 3)C
+(k + 2)(k + 1)C+2]x*0
(k + 2)(k + 1)G,.l-0
O This option
This option
2C, + C, +E(1 – 2k)G
+(k + 2) (k + 1)C.al* - 0
Transcribed Image Text:By shifting the summation index of the following added three series n(n – 1)C, x" + n(n – 1)C,x*-3 –) 4nC, 1" + 6C,x"-0 TOO_BL we get: E[(k - 2)(k - 3)C +(k + 2)(k + 1)C+2]x*0 (k + 2)(k + 1)G,.l-0 O This option This option 2C, + C, +E(1 – 2k)G +(k + 2) (k + 1)C.al* - 0
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