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(c) Show that if b0 = 0, then (g^x) m = 1 (mod p).(to do) (d) Show that if b0 = 1, then (g ^x) m = p - 1 (mod p).(to do)

(c) Show that if b0 = 0, then (g^x) m = 1 (mod p).(to do) (d) Show that if b0 = 1, then (g ^x) m = p - 1 (mod p).(to do)

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Computer Science Since x is a number in the set {0, can write x in binary as: x = b0 · 2 ^0 + b1 · 2^ 1 + b2 · 2 ^2 +...+ If b0 = 0, then x = b1 · 2 ^1 + b2 · 2 ^2 +...+ bt · 2 ^t = 2y, for some integer y, i.e., x is an even number. On the other hand, if b0 = 1, then x = 1 + b1 · 2 ^1 + b2 · 2 ^2 + ... + bt · 2 ^t = 2y + 1, for some integer y, i.e., x is an odd number. Let m : 2^(t -1). 1, 2^ t}, we .. , + bt · 2^ t , (1) where bi are bits. (c) Show that if b0 = 0, then (g^ x ) m = 1 (mod p).(to do) %3D (d) Show that if b0 = 1, then (g ^x ) m = p - 1 (mod p).(to do)
Transcribed Image Text:Computer Science Since x is a number in the set {0, can write x in binary as: x = b0 · 2 ^0 + b1 · 2^ 1 + b2 · 2 ^2 +...+ If b0 = 0, then x = b1 · 2 ^1 + b2 · 2 ^2 +...+ bt · 2 ^t = 2y, for some integer y, i.e., x is an even number. On the other hand, if b0 = 1, then x = 1 + b1 · 2 ^1 + b2 · 2 ^2 + ... + bt · 2 ^t = 2y + 1, for some integer y, i.e., x is an odd number. Let m : 2^(t -1). 1, 2^ t}, we .. , + bt · 2^ t , (1) where bi are bits. (c) Show that if b0 = 0, then (g^ x ) m = 1 (mod p).(to do) %3D (d) Show that if b0 = 1, then (g ^x ) m = p - 1 (mod p).(to do)
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