c) The sides of a triangle are x cm, (x - 5) cm and (x + 3) cm long. If the perimeter is 25 cm, find the length of the three sides. x+x-s+x+3=4s x+x+x-5+3 = 25 3x - 2 = 25 3x = 27 x = 오 d) I think of a number. If I subtract 9 from it and multiply this difference by 4 the result is 32. What is the number I thought of? x-9x4 = 32 Y 19-32 X=17

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter4: Polynomials
Section4.10: Problems Without Solutions
Problem 12P
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244x+6 = 24
64X= 74-6
xX+1, 2+2,+3
17, 1771, 1772, 173
= 17,18,19,20
44x68
x = 17
c) The sides of a triangle are x cm, (x - 5) cm and (x +
3) cm long. If the perimeter is 25 cm, find the length of
the three sides.
x+x-s+x+3=45
x+x+X-5+3= 25
3x - 2 = 25
3x = 27
x = 9₂
d) I think of a number. If I subtract 9 from it and multiply
this difference by 4 the result is 32. What is the number 1
thought of?
x9x4 = 32
X=17
X-9 = 32
4
X-9 = 8
X = 8+9
X=17
Transcribed Image Text:244x+6 = 24 64X= 74-6 xX+1, 2+2,+3 17, 1771, 1772, 173 = 17,18,19,20 44x68 x = 17 c) The sides of a triangle are x cm, (x - 5) cm and (x + 3) cm long. If the perimeter is 25 cm, find the length of the three sides. x+x-s+x+3=45 x+x+X-5+3= 25 3x - 2 = 25 3x = 27 x = 9₂ d) I think of a number. If I subtract 9 from it and multiply this difference by 4 the result is 32. What is the number 1 thought of? x9x4 = 32 X=17 X-9 = 32 4 X-9 = 8 X = 8+9 X=17
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