Please answer this question as soon as possible c. F3 = 0d. F = 0equilibrant of F300 gdynes at 40°, which%3D%3Dmust be used on the force table rather than theforce itself.e. Click net-force vectorf. Click equilibrant vectorg. Calculate sum4.Add weights to the Oo and 90o hangers untilthe system is in equilibrium. The Oo and 90oforces are then the Fx and Fy components,F1F2Fr F Displacement Forcerespectively, of F.Calculated cm /_° g-dynes/_°Procedure:C. Resolution ofa Force into ItsC1. Draw the resolution for 300/ 40° (Use graphComponents Fx and Fy on the Forceрaper)TableGiven a force vector of Fresolve the vector into its x and y components ofFx and Fy.Insert Graph (label all magnitudesand /_ °s on the drawings andlist the scale used)300 g-dynes at 40°,%3DC2. Use analytical method (use the same scale as1. Given a force vector of F300 g-dynes atthe drawing) Show calculationsFx Fy40°, resolve the vector into its x and ycomponents of Fx and Fy. Record the results inFx1 Fy1Fx2 Fy2EFx EFythe data table.2.Clamp pulleys at 220°, 90° and 0° on theforce table.C3. Use simulation (use the same scale as the3. Use a weight hanger to place a total of 300 gon the 220° pulley string. This force is thedrawing)

Given force vector, F=300 g-dynes oriented at 400. Its components along X and Y axis are given by…

c. F3 = 0 equilibrant ofF = 300 gdynes at 40°, which must be used on the force table rather than the d. F = 0 force itself. e. Click net-force vector 4.Add weights to the Oo and 90o hangers until the system is in equilibrium. The Oo and 90o forces are then the Fx and Fy components, f. Click equilibrant vector g. Calculate sum F1F2FF F Displacement Force Calculated cm/_° g-dynes/_° C. Resolution of a Components Fx and Fy on the Force respectively, of F. Procedure: Force into Its c1. Draw the resolution for 300/ 40° (Use graph рaper) Table Given a force vector of F = 300 g-dynes at 40°, resolve the vector into its x and y components of Insert Graph (label all magnitudes and /_ °s on the drawings and list the scale used) Fx and Fy. C2. Use analytical method (use the same scale as 1. Given a force vector of F = 300 g-dynes at 40°, resolve the vector into its x and y the drawing) Show calculations Fx Fy components of Fx and Fy. Record the results in Fx1 Fy1 Fx2 Fy2 ΣΕχ ΣΕy the data table. 2.Clamp pulleys at 220°, 90° and 0° on the force table. 3. Use a weight hanger to place a total of 300 g on the 220° pulley string. This force is the C3. Use simulation (use the same scale as the drawing)

c. F3 = 0 equilibrant ofF = 300 gdynes at 40°, which must be used on the force table rather than the d. F = 0 force itself. e. Click net-force vector 4.Add weights to the Oo and 90o hangers until the system is in equilibrium. The Oo and 90o forces are then the Fx and Fy components, f. Click equilibrant vector g. Calculate sum F1F2FF F Displacement Force Calculated cm/_° g-dynes/_° C. Resolution of a Components Fx and Fy on the Force respectively, of F. Procedure: Force into Its c1. Draw the resolution for 300/ 40° (Use graph рaper) Table Given a force vector of F = 300 g-dynes at 40°, resolve the vector into its x and y components of Insert Graph (label all magnitudes and /_ °s on the drawings and list the scale used) Fx and Fy. C2. Use analytical method (use the same scale as 1. Given a force vector of F = 300 g-dynes at 40°, resolve the vector into its x and y the drawing) Show calculations Fx Fy components of Fx and Fy. Record the results in Fx1 Fy1 Fx2 Fy2 ΣΕχ ΣΕy the data table. 2.Clamp pulleys at 220°, 90° and 0° on the force table. 3. Use a weight hanger to place a total of 300 g on the 220° pulley string. This force is the C3. Use simulation (use the same scale as the drawing)