Calculate the coefficient of permeability in mm/s of a soil sample, 6 cm in height and 50 cm2 in cross sectional area, if a quantity of water equal to 430 ml passed down in 10 minutes, under an effective constant head of 40 cm. a.625 X 10^-2 b.5.9 x 10^-2 c.1.6 X 10^-5 d.2.15 x 10^-2

Calculate the coefficient of permeability in mm/s of a soil sample, 6 cm in height and 50 cm2 in cross sectional area, if a quantity of water equal to 430 ml passed down in 10 minutes, under an effective constant head of 40 cm. a.625 X 10^-2 b.5.9 x 10^-2 c.1.6 X 10^-5 d.2.15 x 10^-2

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter2: Soil Deposits-origin, Grain-size, And Shape

Section: Chapter Questions

Problem 2.4P: For a soil, given: D10 = 0.08 mm D30 = 0.22 mm D60 = 0.41 mm Calculate the uniformity coefficient...

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Concept explainers

Field applications of hydraulic conductivity

Hydraulic conductivity is one of the hydraulic properties of soil defined as a measurement of the ability of a porous medium to permit water movement or fluid flow through it. It is denoted by the letter K. It is influenced by the density and viscosity of the fluid. It is also called permeability. Hydraulic conductivity is defined as the ratio of velocity to the hydraulic gradient. The different methods used to determine the hydraulic conductivity are laboratory methods (constant head permeability tests and falling head tests), in-situ field methods (pumping in and pumping out tests), small scale field tests (infiltration tests and slug tests), and indirect methods such as estimation from grain size, consolidation test data, and horizontal capillary test. The pedotransfer function (PTF) method is a specific empirical estimating approach employed in the soil sciences is also used to determine the hydraulic conductivity of the soil.

Question

a.625 X 10^-2

b.5.9 x 10^-2

c.1.6 X 10^-5

d.2.15 x 10^-2

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