Calculate the discharge through the channel and the floodway (shown in the Figure below) for steady uniform flow, with S= 0.0009 and y = 8 ft. n=0.025 12 m 5 m [Σ, Pin n=0.040 1 Pin²+ Propags 120 m Use the following equivalent channel roughness formula due to Pavlovskii (1931)* ne = Side slopes 1:1 For 25,000 cfs flow through the channel above, find the depth of flow in the floodway when the slope of the energy grade line is 0.0004.

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Calculate the discharge through the channel and the floodway (shown
in the Figure below) for steady uniform flow, with S = 0.0009 and
y = 8 ft.
n = 0.025
ne =
12 m
5 m
n=0.040
√ [EXP²] +
Р
Paper
120 m
ZAZ
Use the following equivalent channel roughness formula due to Pavlovskii
(1931)*
Side
slopes
1:1
For 25,000 cfs flow through the channel above, find the depth of flow
in the floodway when the slope of the energy grade line is 0.0004.
Transcribed Image Text:Calculate the discharge through the channel and the floodway (shown in the Figure below) for steady uniform flow, with S = 0.0009 and y = 8 ft. n = 0.025 ne = 12 m 5 m n=0.040 √ [EXP²] + Р Paper 120 m ZAZ Use the following equivalent channel roughness formula due to Pavlovskii (1931)* Side slopes 1:1 For 25,000 cfs flow through the channel above, find the depth of flow in the floodway when the slope of the energy grade line is 0.0004.
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