Calculate the displacement of B-D-F points using the energy method or the Castigliano method. Cross section of all circular members have a radius of 50 cm and a modulus of elasticity of 207 GPa
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- Consider the modulus of elasticity of aluminum to be 10,000 lb / in2.Verify homogeneity in the units. An aluminum block of rectangular cross section is subjected to an axial compressive force, if the side measuring 1.5 in changes in length to 1.500132 in, determine the poisson's ratio and the new length of the side measuring 5 cm.Consider the modulus of elasticity of aluminum to be 10,000 lb / in2.Verify homogeneity in the units. An aluminum block of rectangular cross section is subjected to an axial compressive force, if the side measuring 1.5 in changes in length to 1.500132 in, determine the new length of the side measuring 5 cm.Choose correct answer: A mild steel rod of 15mm diameter that is 1.5.m in length is elongated by 0.15cm along its longitudinal direction by a load of 15 kN. The intensity of stress is 0.08488 N/mm2 48.88 N/mm2 84880 N/mm2 84.88 N/mm2
- Determine the changes in length, breadth and thickness of a steel bar which is 4 m long, 30 mm wide and 20 mm thick and is subjected to an axial pull of 30 kN in the directions of its length. Take Young’s Modulus as 70 GPa and Poisson’s ratio as 0.3.Determine the elongation of an aluminium hollow cylinder of an inner diameter of 1.45 cm & the external diameter of 24.7 mm is subjected to an elastic tensile load of 251 kN. Take the elastic modulus of the aluminum specimen as 71 GPa and the initial length of the hollow cylinder as 198 mm. Solution: Cross-sectional Area (in mm2) = Stress-induced (in N/mm2) = Strain-induced (at least 3 decimal places accuracy)= Elongation (in mm) =Determine the elongation of an aluminium hollow cylinder of an inner diameter of 1.22 cm & the external diameter of 23.4 mm is subjected to an elastic tensile load of 228 kN. Take the elastic modulus of the aluminum specimen as 71 GPa and the initial length of the hollow cylinder as 187 mm. Solution: i) Cross-sectional Area (in mm2) = ii) Stress-induced (in N/mm2) = iii) Strain-induced (at least 3 decimal places accuracy)= iv) Elongation (in mm) =
- Determinethe change in diameter of a circular steel rod axially loaded in compression where the diameter is 4.8cm and the axial strain of –0.0021 with poisson's ratio of 0.27.Using the previous answers; determine the angular deflection in both shafts. Both shafts are 20 cm long and the modulus of rigidity for the material is 60GN/m^2.Consisting of chrome-nickel and bronze,the largest horizontal P force it can carry, and chromium-nickelCalculate the length change that will occur in the cable.Cross Section Areas: A chrome-nickel = 3 cm2A bronze = 6 cm2Elasticity modules: E chrome-nickel = 215 Gpa, E bronze = 90 GpaSafety Stresses: (σem) bronze = 100 Mpa, (σem) chromium-nickel = 600 Mpa
- A stepped circular bar having diameters 20 mm, 15: mm and 10 mm over axial lengths of 100 mm, 80mm and 60mm is subjected to an axial tensile force of 5 KN. If E= 100 x 103 N/mm2 and 1/m = 0.32 for the material of bar, determine total change in length and change in each diameter.A copper cylinder with a length of 1.5 m and diameter of 4 cm undergoes compression. Bulk Modulus (14*10^10 Pa) What will be the bulk strain of the copper rod if pressure is applied to reduce its volume to 0.00089 m3? How much pressure was applied to the copper rod? Calculate the percent change in volume of the copper rod.Let’s consider a rod having a solid circular cross-section with diameter of 6 mm and it is made of a material having a Young’s modulus E = 200 Gpa and a Poisson’s ratio of 0.3. If a tensile force F is subjected to that rod cross-section, the diameter becomes 5.998 mm. determine the applied force F. Select one: F = 6283 N F = 10472 N F = 4189 N F = 5236 N F = 13090 N F = 15708 N