Calculate the network address, broadcast address, and subnet mask for 174.50.50.23/26.
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A: The IP address is 192.168.16.0 The netid is 22. This means the number of host bits is 32-22=10
Q: For the subnet mask bits /24, what is the number of /25 subnets? a.1 b.2 c.4 d.8
A: Given , For the subnet mask bits /24, what is the number of /25 subnets?a.1 b.2 c.4 d.8
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A: Find the required answer given as below :
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A:
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A: Given 192.168.3.55/24 In this /24 means number of network bits is 24 and number of host bits is 8.…
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A: The answer is given in step 2.
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A: GIVEN DATA
Q: for
A: It belongs to class B network
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Calculate the network address, broadcast address, and subnet mask for 174.50.50.23/26.
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- 40. Determine the first useable address, the last useable address, the network address, the subnet mask and the subnet broadcast address for the 125th useable subnet when subnetting the following: a. 10.0.0.0 when borrowing 14 bits b. 172.20.0.0 when borrowing 7 bitsCalculate the network address, broadcast address, and subnet mask for 10.10.110.85/27Using VLSM subneting, subnet 192.168.42.0/24 for 4 departments. Include the subnet, first host, last host, broadcast and Mask for these 4 departments
- Based on the subnet mask, 255.255.255.0, how many computers can be addressed on the subnet on which the computer is located?I need to write the subnet mask, subnet address, broadcast address and valid host range for 192.168.100.25/30For the subnet mask bits /24, what is the number of /25 subnets?a.1 b.2 c.4 d.8
- Identify the default subnet mask and CIDR value for 167.225.138.254 Identify the respective class, network address and host address of 167.225.138.254A supernet has first address of 205.16.32.0 and a supernet mask of 255.255.248.0. Prove that the range of addresses is from 205.16.32.0 to 205.16.39.0PART I: Network Address Use ANDing process to determine the Network Address. Show your Solution1. 172.21.182.71 Subnet Mask: 255.255.255.1282. 10.36.191.68 Subnet Mask: 255.255.255.2483. 10.60.208.98 Subnet Mask: 255.255.224.0
- What is the network number of address 10.30.45.22 with a subnet mask of 255.224.0.0?Calculate the number of subnets for each given Network Address and broadcast address and valid host addresses for each subnet: a. 11.1.0.0/12 b. 133.11.1.0/25 c. 198.10.1.0/28 d. 15.10.10.0/19 e. 212.147.16.0/30 Please the solution be simple and not be handwritten. Thank you1.1 Consider the given IP address and subnet mask, write using CIDR notation. IP address: 192.168.1.0 & subnet mask: 255.255.255.0 [2] IP address: 10.0.0.0 & subnet mask: 255.255.255.128 [2] IP address: 172.16.00 & subnet mask: 255.255.0.0 [2]