Part 1For the simply supported beam subjected to the loading shown, derive equations for the shear force Vand the bending moment Mfor any location in the beam. (Place the origin at point A.) Let a-14.0 ft, b-5.5 ft, c- 8.0 ft, w - 9 kips/ft and M - 260 kip-ft.Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequentparts of this GO exercise.Calculate the reaction forces Ay and Cy acting on the beam. Positive values for the reactions are indicated by the directions of thered arrows shown on the free-body diagram below. (Note: Since Ax - 0, it has been omitted from the free-body diagram.)- 0,BAnswers:Ay-kipskipsPart 2Determine the shear force acting at each of the following locations:(a) x - 0+ ft (i.e., just to the right of support A)(b) x - 14.0 ft (i,e., at point B)(c) x - 19.5- ft (i.e., just to the left of the support C)(d) x - 19.5+ ft (i.e., just to the right of the support (C)(e) x - 26.5 ftNote that x - 0 at support A. When entering your answers, use the shear-force sign convention detailed in Section 7.2.Answers:(a)V-ikips(b)V-ikips(c)V-kips(d)V-kips(e)kips Part 3Determine the bending moment acting at each of the following locations:(a) x = 14.0- ft (i.e., just to the left of point B)(b) x = 14.0+ ft(i.e., just to the right of point B)(c)x = 19.5 ft (i.e. at point C)(d) x = 26.5 ftNote that x = 0 at support A. When entering your answers, use the shear-force sign convention detailed in Section 7.2.Answers:(а) М-kips-ft(b) М-kips-ft(c) M-kips-ft(d) M =ikips-ftPart 4Use your shear-force and bending-moment diagrams to determine the maximum positive bending moment, Mmax pos, themaximum negative bending moment, Mmax, neg, and their respective locations, Xmax, pos and Xmax, neg. When entering your answersfor the maximum bending moments, use the shear-force and bending-moment sign conventions detailed in Section 7.2. Themaximum negative bending moment is the negative moment with the largest absolute value. Enter the maximum negativebending moment as a negative value.Answers:Mmax, poskips-ft Xmax, posftMmax, neg=kips-ft Xmax, negft

Answered: Image /qna-images/answer/e16b8c98-7f35-4cfc-be7b-3cfec2089a83.jpg

Calculate the reaction forces Ay and Cy acting on the beam. Positive values for the reactions are indicated b red arrows shown on the free-body diagram below. (Note: Since Ax - 0, it has been omitted from the free-b B Answers: Ay- kips kips Part 2 Determine the shear force acting at each of the following locations: (a) x = 0+ ft (i.e., just to the right of support A) (b) x - 14.0 ft (i,e., at point B) (c) x - 19.5- ft (i.e., just to the left of the support C) (d) x - 19.5+ ft (i.e., just to the right of the support (C) (e) x - 26.5 ft Note that x-0 at support A. When entering your answers, use the shear-force sign convention Answers: (a) V- kips (b) V- i kips (c) V- kips (d) V- kips

Calculate the reaction forces Ay and Cy acting on the beam. Positive values for the reactions are indicated b red arrows shown on the free-body diagram below. (Note: Since Ax - 0, it has been omitted from the free-b B Answers: Ay- kips kips Part 2 Determine the shear force acting at each of the following locations: (a) x = 0+ ft (i.e., just to the right of support A) (b) x - 14.0 ft (i,e., at point B) (c) x - 19.5- ft (i.e., just to the left of the support C) (d) x - 19.5+ ft (i.e., just to the right of the support (C) (e) x - 26.5 ft Note that x-0 at support A. When entering your answers, use the shear-force sign convention Answers: (a) V- kips (b) V- i kips (c) V- kips (d) V- kips

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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