Calculate the slope and deflection atB and E of the beam and loadings shown using double integration method. The section of the beam is tubular with outer diameter of 500mm and inner diameter of 200mm. Take E=20GPa.

Problem 1) A simply supported beam is loaded as shown in Figure 1-A. Use E = 40 MPa and I = 5 x 10⁶ mm⁴. b) Determine the deflection at point B

For the simply supported beam loaded as shown, determine the deflection at the midspan of the beam. Use E 200 GPa and I = 15 x 106 mm. Double integration. (Boundary method)

1. Draw the deflection diagram for the following figure 2. Use the double integration method to derive the Elastic curve equation (moment equation). Then use the moment equation to determine the deflection values. Use the conjugate beam method to determine deflections Tiguiv J. R= 24 kips w = 2 kips/ft 'P = 13.5 kips C B- 40 kip- ft 1 RA = 21.5 kips Rc = 16 kips 12 (a)

For the beam and loading shown, use discontinuity functions to compute (a) the slope of the beam at B and (b) the deflection of the beam at A. Assume a constant value of El = 125000 kip-ft² for the beam; wo = 3.0 kips/ft, LAB = 8 ft. LBc = 4 ft. wo LBC LAB Answer: (a) 0g = 0.00869 (b) VA = rad in. C

Compute the deflection at C using conjugate beam method. Assume EI to be constant, E = 200GPa, I = 500 x 10^6 mm^4.

If x is measured from the left end of the beam, compute for the deflection at x=7m. Also, determine the location and magnitude of the maximum deflection. Use double integration method. The flexural rigidity of the beam is IE.

2. By using Double Integration Method, Determine the deflection at the free end of the beam shown -5 m- 180 KN B -5 m- El = constant E = 70 GPa I = 2,340 (106) mm4 15 kN/m -4 m- D

Determine the following unknowns on the beam shown below using Conjugate-Beam Method. Consider 250 mm x 250 mm section and E = 200 GPa. Show complete and organized solution. d. Maximum deflection on the beam in m Valuea = 4.8b = 28c = 11 Thank you very much!

(CONJUGATE-BEAM METHOD) Determine the maximum deflection of the steel beam shown below. E = 200 GPa | = 60(10°) mmª P = 6.4 kN a = 9 m b = 3 m P a b