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Calculate the work for the expansion of 3 moles of B,H6 at 40°C from 2.74 L to 3.89 L using van der Waals equation. The correction for intermolecular forces (a) is 6.048 bar L/mol? and the adjustment factor of the volume (b) is 0.07437 L/mol. The general equation for van der Waals is written below: + a -- b| = RT

Calculate the work for the expansion of 3 moles of B,H6 at 40°C from 2.74 L to 3.89 L using van der Waals equation. The correction for intermolecular forces (a) is 6.048 bar L/mol? and the adjustment factor of the volume (b) is 0.07437 L/mol. The general equation for van der Waals is written below: + a -- b| = RT

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Calculate the work for the expansion of 3 moles of B,H6 at 40°C from 2.74 L to 3.89 L using van der Waals equation. The correction for intermolecular forces (a) is 6.048 bar L/mol? and the adjustment factor of the volume (b) is 0.07437 L/mol. The general equation for van der Waals is written below: n 2- P + a = RT A. 2352.2376J C. 2118.1071J B. -2352.2376 J D. -2118.1071 J
Transcribed Image Text:Calculate the work for the expansion of 3 moles of B,H6 at 40°C from 2.74 L to 3.89 L using van der Waals equation. The correction for intermolecular forces (a) is 6.048 bar L/mol? and the adjustment factor of the volume (b) is 0.07437 L/mol. The general equation for van der Waals is written below: n 2- P + a = RT A. 2352.2376J C. 2118.1071J B. -2352.2376 J D. -2118.1071 J
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