2 m-1)° = y + 0.6 m = 1 m 10 S

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
8th Edition
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
Publisher:Kreith, Frank; Manglik, Raj M.
Chapter4: Numerical Analysis Of Heat Conduction
Section: Chapter Questions
Problem 4.43P
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Calculate velocity gradients and shear stress for ?=0,0.2,0.4, and 0.6 m, if the velocity profile is a quarter‐circle having its center 0.6 m from the boundary. The fluid viscosity is 7.5×10−4 Ns/m2. The velocity profile is given as:

 

2
и
y
+
0.6 m
= 1
10
S
Transcribed Image Text:2 и y + 0.6 m = 1 10 S
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