ey.com/was/ui/v2/assessment-player/index.html?launchld%3D1 /836 2 0/10 Question 3 of 11 <> X Your answer is incorrect. Use the dynamic points to graph the polynomial = x (x2 - 1). Since p(-x) = -p(x) for all real x, we know that p(x) is an odd function. The fixed points represent points of interest: x-intercepts, relative extrema, and inflection points. NOTE: Do not try to position a dynamic point at (0,0), as that point has already been noh Jof paydou6 (1.3,0.5) (0.5,0.3) (-ז '0) (o) (-1.4,-1.1) rch

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