10 The masses m; are located at the points Pj. Find the moments Mx and My and the center of mass of the system m1 = 1, m2 = 4, m3 = 53; P1 = (2, -6), P2 = (-3, 2), P3 = (3, 4) %3D %3D %3D %3D %3D Step 1 The total mass of the system is the sum of the individual masses. m = m1 + m2 + m3 Step 2 In' terms of m¡ and (xi, Yi), we have the following formulas. 3. %3D = XW m;Yi 3 5. My Step 3 Therefore, we can evaluate and find My = 5 X and My: 22 Submit Skip (you cannot come back). MacBook Pro # $ 5. 9
10 The masses m; are located at the points Pj. Find the moments Mx and My and the center of mass of the system m1 = 1, m2 = 4, m3 = 53; P1 = (2, -6), P2 = (-3, 2), P3 = (3, 4) %3D %3D %3D %3D %3D Step 1 The total mass of the system is the sum of the individual masses. m = m1 + m2 + m3 Step 2 In' terms of m¡ and (xi, Yi), we have the following formulas. 3. %3D = XW m;Yi 3 5. My Step 3 Therefore, we can evaluate and find My = 5 X and My: 22 Submit Skip (you cannot come back). MacBook Pro # $ 5. 9
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
Problem 18T
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Transcribed Image Text:10
The masses m; are located at the points Pj. Find the moments Mx and My and the center of mass of the system
m1 = 1, m2 = 4, m3 = 53;
P1 = (2, -6), P2 = (-3, 2), P3 = (3, 4)
%3D
%3D
%3D
%3D
%3D
Step 1
The total mass of the system is the sum of the individual masses.
m = m1 + m2 + m3
Step 2
In' terms of m¡ and (xi, Yi), we have the following formulas.
3.
%3D
= XW
m;Yi
3
5.
My
Step 3
Therefore, we can evaluate and find My = 5
X and My:
22
Submit
Skip (you cannot come back).
MacBook Pro
#
$
5.
9
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