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Asked Dec 8, 2019
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Step 1

It is given that f is continuous and differentiable such that

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-[ r A(x) = FC f (t) dt

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Step 2

We know th...

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Leibniz rule: ch(x) d f(t) dt ) = f(h(x)) · h'(x) – f(g(x)) · g'(x) g(x) -ź([roa)-rc» -1 da d A'(x) dx dx - f(a) · dx dx dx da = f(x) · (1) – f(a) · (0) %3D dx dx A'(x) = f (x) differentiating both sides of the above equation, we get A"(x) = f'(x) at x = c, f'(c) = A"(c) -- (1) %3|

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Calculus

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