Create an Java Postfix converter using the algorithm provided.Thank you Algorithm convertToPostfix (infix)11 Converts an infix expression to an equivalent postfix expression.operatorStack = a new empty stackpostfix = a new empty stringwhile (infix has characters left to parse){nextCharacter = next nonblank character of infixswitch (nextCharacter){}}while{case variable:Append nextCharacter to postfixbreakcase 'Λ'operatorStack.push(nextCharacter)breakcase '+': case: casewhile (!operatorStack.isEmpty() andprecedence of nextCharacter <= precedence of operatorStack.peek ())Append operatorStack. peek () to postfixoperatorStack.pop(){}breakcase '(':IoperatorStack.push(nextCharacter)I* IoperatorStack.push(nextCharacter)breakcase ')': // Stack is not empty if infix expression is validoperatorStack.pop()=topOperatorwhile (topOperator != '('){: case '/' :Append topOperator to postfixtopOperator = operatorStack.pop()(!operatorStack.isEmpty())}breakdefault: break // Ignore unexpected characters}return postfixtopOperator = operatorStack.pop()Append topOperator to postfix

Step-1) Creating function that converts an infix expression to postfix expression.Step-2) Then,…

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Create an Java Postfix converter using the algorithm provided. Thank you

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter18: Stacks And Queues

Section: Chapter Questions

Problem 15SA

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Question

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Create an Java Postfix converter using the algorithm provided.

Thank you

Algorithm convertToPostfix (infix)
11 Converts an infix expression to an equivalent postfix expression.
operatorStack = a new empty stack
postfix = a new empty string
while (infix has characters left to parse)
{
nextCharacter = next nonblank character of infix
switch (nextCharacter)
{
}
}
while
{
case variable:
Append nextCharacter to postfix
break
case 'Λ'
operatorStack.push(nextCharacter)
break
case '+': case
: case
while (!operatorStack.isEmpty() and
precedence of nextCharacter <= precedence of operatorStack.peek ())
Append operatorStack. peek () to postfix
operatorStack.pop()
{
}
break
case '(':
I
operatorStack.push(nextCharacter)
I* I
operatorStack.push(nextCharacter)
break
case ')': // Stack is not empty if infix expression is valid
operatorStack.pop()
=
topOperator
while (topOperator != '(')
{
: case '/' :
Append topOperator to postfix
topOperator = operatorStack.pop()
(!operatorStack.isEmpty())
}
break
default: break // Ignore unexpected characters
}
return postfix
topOperator = operatorStack.pop()
Append topOperator to postfix

Process or set of rules that allow for the solving of specific, well-defined computational problems through a specific series of commands. This topic is fundamental in computer science, especially with regard to artificial intelligence, databases, graphics, networking, operating systems, and security.

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