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can be calculated by the following equation. (V4H9 |tan(t) /4gH 4L v = Note that (H) is the primary head in meter, (L) is the length of the pipe in meter, (g) is the gravity = 9.81 (m/s²) and (t) is time in second L H v Figure Q1 With starting interval of [1.5, 2.5] for (H), [use five decimal places in your all answers and calculations]. a) Conduct three iterations to find the needed head to achieve a velocity of 22 m/s in 2.5 second with pipe length (L) of 3 meter using bisection method.

can be calculated by the following equation. (V4H9 |tan(t) /4gH 4L v = Note that (H) is the primary head in meter, (L) is the length of the pipe in meter, (g) is the gravity = 9.81 (m/s²) and (t) is time in second L H v Figure Q1 With starting interval of [1.5, 2.5] for (H), [use five decimal places in your all answers and calculations]. a) Conduct three iterations to find the needed head to achieve a velocity of 22 m/s in 2.5 second with pipe length (L) of 3 meter using bisection method.

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
Chapter2: Graphical And Tabular Analysis
Section2.1: Tables And Trends
Problem 1TU: If a coffee filter is dropped, its velocity after t seconds is given by v(t)=4(10.0003t) feet per...
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1- Figure Q1 shows water discharged from a tank with velocity v (m/s). The velocity can be calculated by the following equation. v = |tan(t) /4gH 4L Note that (H) is the primary head in meter, (L) is the length of the pipe in meter, (g) is the gravity = 9.81 (m/s²) and (t) is time in second H Figure Q1 With starting interval of [1.5, 2.5] for (H), [use five decimal places in your all| answers and calculations]. a) Conduct three iterations to find the needed head to achieve a velocity of 22 m/s in 2.5 second with pipe length (L) of 3 meter using bisection method.
Transcribed Image Text:1- Figure Q1 shows water discharged from a tank with velocity v (m/s). The velocity can be calculated by the following equation. v = |tan(t) /4gH 4L Note that (H) is the primary head in meter, (L) is the length of the pipe in meter, (g) is the gravity = 9.81 (m/s²) and (t) is time in second H Figure Q1 With starting interval of [1.5, 2.5] for (H), [use five decimal places in your all| answers and calculations]. a) Conduct three iterations to find the needed head to achieve a velocity of 22 m/s in 2.5 second with pipe length (L) of 3 meter using bisection method.
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