Can I get a step by step for this question? Using the data presented for the given soil sample, determine the soil classification using the ASTM and the AASHTO Soil classification system. Give the group index if needed. The soil is inorganic soil. Sieve No. 19mm (¾ in.) 12.5mm (1/2in.) No. 4 (4.75 mm) No. 10 (2.00 mm). No. 20 (0.850 mm) No. 40 (0.425 mm) No. 100 (0.150 mm) No. 200 (0.075 mm) Percent Passing 100 83 67 56 54 45 39 36 Cu: 5.5 and Cc: 1.8 Atterberg limits: Liquid limit: 20%, Plasticity Index: 6%

Can I get a step by step for this question? Using the data presented for the given soil sample, determine the soil classification using the ASTM and the AASHTO Soil classification system. Give the group index if needed. The soil is inorganic soil. Sieve No. 19mm (¾ in.) 12.5mm (1/2in.) No. 4 (4.75 mm) No. 10 (2.00 mm). No. 20 (0.850 mm) No. 40 (0.425 mm) No. 100 (0.150 mm) No. 200 (0.075 mm) Percent Passing 100 83 67 56 54 45 39 36 Cu: 5.5 and Cc: 1.8 Atterberg limits: Liquid limit: 20%, Plasticity Index: 6%

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter2: Soil Deposits-origin, Grain-size, And Shape

Section: Chapter Questions

Problem 2.14P

See similar textbooks

Similar questions

Can I get a step by step for this question? Using the data presented for the given soil sample, determine the soil classification using the ASTM and the AASHTO Soil classification system. Give the group index if needed. The soil is inorganic soil. Sieve No. 19mm (¾ in.) 12.5mm (1/2in.) No. 4 (4.75 mm) No. 10 (2.00 mm) No. 20 (0.850 mm) No. 40 (0.425 mm) No. 100 (0.150 mm) No. 200 (0.075 mm) Percent Passing 100 95 63 50 44 37 28 22 Cu: 5.5 and Cc: 1.8 Atterberg limits: Liquid limit. 33%, Plasticity Index: 17%.
40.) The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 96 No. 8 2.380 80 No. 10 2.000 78 No. 20 0.840 61 No. 40 0.420 56 No. 60 0.250 48 No. 100 0.150 39 No. 200 0.075 33 Characteristics of No. 40 Fraction LL 38 PL 29 A. A-2-4(0) B. A-1-b(0) C. A-1-a(0) D. A-3(0) E. A-2-5(0)
The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 100 No. 8 2.380 100 No. 10 2.000 95 No. 20 0.840 81 No. 40 0.420 74 No. 60 0.250 69 No. 100 0.150 55 No. 200 0.075 51 Characteristics of No. 40 Fraction LL 48 PL 40 A. A-5(3) B. A-7-5(4) C. None of these. D. A-5(4) E. A-7-6(3)
Classify the soil using AASHTO. The liquid limit and plastic limit are found to be 30 and 20, respectively. The following data are obtained: Percent passing No. 4 sieve: 100% Percent passing No. 10 sieve: 91% Percent passing No. 40 sieve: 60% Percent passing No. 200 sieve: 20%
A Sample of soil was tested in the laboratory with the following results Liquid limit =30% Plastic limit =12% U.S. Sieve Size Percentage Passing 3/8 in. 100.0 No. 4 76.5 No. 10 60.0 No. 40 39.7 No. 200 15.2 Classify the soil sample by the USCS classification system.
A Sample of soil was tested in the laboratory, and results of the laboratory tests were as follows: Liquid limit =42% Plastic limit =16% U.S. Sieve Size Percentage Passing No. 4 100 No. 10 93.2 No. 40 81.0 No. 200 60.2 Classify the soil sample by the AASHTO classification system.
Analyze each statement (A and B) whether they are true or false. Use the choices below in answering each item; A statement A is true B statement B is true C both A and B are true D neither A nor B are true (A) As the soil becomes compacted, both bulk density and particle density increase. (B) Porosity is inversely proportional to bulk density, meaning as bulk density increases percent porosity decreases, and vice versa.
A Sample of soil was tested in the laboratory, and the test results were listed as follows. Classify the soil by both the AASHTO system and the Unified Soil classification system. Liquid Limit = 33% Plastic Limit = 27% Mechanical grain-size analysis: Sieve No. Percentage Passing 4 90 10 77 40 65 200 12
From the given data, shows a sieve analysis of soil samples SIEVE NO. PERCENT PASSING PERCENT RETAINED SOIL A SOIL B SOIL C SOIL D 4 100 100 0 5 8 93 85 5 10 10 87 61 21 18 20 65 49 33 24 40 55 39 49 37 60 44 24 55 40 100 37 22 58 46 200 35 18 63 49 LL 39 25 42 45 PL 20 22 27 35 Cu 6 8 7 5 a.) Classify Soil A using AASHTO method b.) Classify Soil B using AASHTO method c.) Classify Soil C using USCS method d.) Classify Soil D using USCS method Please answer this asap. For upvote. Thank you
04- The following results were obtained by a mechanical sieve analysis. Classify the soil using the Unified Soil Classification System (USCS). Sieve Analysis, % Passing by Weight than No. 4: 30%, than No. 40: 40%, than No. 200: 30%; liquid limit = 33; plastic limit = 12.
Classify the soil by the Unified classification system. The results of the particle-size analysis of a soil are as follows: Percent passing through the No. 10 sieve = 90% Percent passing through the No. 40 sieve = 65% Percent passing through the No. 200 sieve = 15% The liquid limit and plasticity index of the minus No. 40 fraction of the soil are 35 and 15, respectively. Note: Solution is not required for PS3. Enter your answers here: Group symbol (all upper case) = Group name (all lower case) =
Analyze each statement (A and B) whether they are true or false. Use the choices below in answering each item; A statement A is true B statement B is true C both A and B are true D neither A nor B are true (A) 50 g soil is suspended in a liter aqueous solution, the hydrometer reading at t=0 is 40. (B) In sedimentation analysis, sand settles first, followed by silt, and clay particles settle last.