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Can someone kindly explain how the answer sheet got (1,0) and (2,1)?

Can someone kindly explain how the answer sheet got (1,0) and (2,1)?

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.5: Rational Functions
Problem 8E
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Can someone kindly explain how the answer sheet got (1,0) and (2,1)? I am asked to find the domain and range, asymptotes, intercepts and transformation. Thank you so much.
(b) Graph y = log3(x-3) - 6 horizontal shift : right 3 vertical shift: down 6 vertical asymptote: >= 3 no horizontal asymptote domain: {XER | x 73} range:{YER} x-int: C732, 0) y-int : none parent function : y=logzCx) -10 -8 -6 vertical asymptote >=1 -4 10 -2 Y 12 8 6 4 2 -2 -4 -6 -8 -10 1=' TT 2 x=3 tco 6 8 +X 10
Transcribed Image Text:(b) Graph y = log3(x-3) - 6 horizontal shift : right 3 vertical shift: down 6 vertical asymptote: >= 3 no horizontal asymptote domain: {XER | x 73} range:{YER} x-int: C732, 0) y-int : none parent function : y=logzCx) -10 -8 -6 vertical asymptote >=1 -4 10 -2 Y 12 8 6 4 2 -2 -4 -6 -8 -10 1=' TT 2 x=3 tco 6 8 +X 10
ZDbt71 b) Graph y = log₂ (x-2)-3 Base Fuc, y= log₂x shift right 2 (1,0) (2,1) x=0 I →shift down 3 x=2 Final fuc: D:{XER/x>2} R: {y€R} asymp: x=2 анутрі x-int: (10,0) -10 -8 -6 -4 X=DA 10 -2 8 61- 4 T -2 -4 -6 -8 -10- TO 2- J x=2 4 6 y= log₂x 10 y= log₂ (x-2) -3 HW: Graphs of Exponential Functions Worksheet, Pg. 338 #1-8
Transcribed Image Text:ZDbt71 b) Graph y = log₂ (x-2)-3 Base Fuc, y= log₂x shift right 2 (1,0) (2,1) x=0 I →shift down 3 x=2 Final fuc: D:{XER/x>2} R: {y€R} asymp: x=2 анутрі x-int: (10,0) -10 -8 -6 -4 X=DA 10 -2 8 61- 4 T -2 -4 -6 -8 -10- TO 2- J x=2 4 6 y= log₂x 10 y= log₂ (x-2) -3 HW: Graphs of Exponential Functions Worksheet, Pg. 338 #1-8
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