Using the method of substitution,I! = [ z²(1 + 2x³)³dx = [ f(u)duwhereU=du: =f(u) =Using the above information:[ x²(1 + 2x³)²dx= [ f(u)du=||dx(in terms of u)(in terms of x)Note: Don't forget the constant of integration in the last two blanks.

Given integral:- I=∫x21+2x32dx

Answered: Using the method of substitution, I = […

Using the method of substitution, I = [ x²(1 + 2x³¹)³dx = [ f(u)du where u= du = f(u) = Using the above information: [ x²(1 + 2x³)³dx - f(u)du = || da (in terms (in terms

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)

6th Edition

ISBN:9781337111348

Author:Bruce Crauder, Benny Evans, Alan Noell

Publisher:Bruce Crauder, Benny Evans, Alan Noell

ChapterA: Appendix

SectionA.2: Geometric Constructions

Problem 10P: A soda can has a volume of 25 cubic inches. Let x denote its radius and h its height, both in...

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Question

100%

Using the method of substitution,
I
! = [ z²(1 + 2x³)³dx = [ f(u)du
where
U=
du: =
f(u) =
Using the above information:
[ x²(1 + 2x³)²dx
= [ f(u)du
=
||
dx
(in terms of u)
(in terms of x)
Note: Don't forget the constant of integration in the last two blanks.

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Follow-up Questions

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Follow-up Question

These are incorrect

u= 1+2x^3
-lu = 6x^2
f(u) = 4^2/6
Using the above information:
[ x² (1+2x³)²dx
= [ f(u)du
4^3/10 + C
(1+2x^3)^3/10 +C
dx
(in terms of u)
(in terms of x)

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Follow-up Question

Can you clairy what answer goes where?

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