Can you explain how we get the numbers i underlined in blue for the shear diagram
Can you explain how we get the numbers i underlined in blue for the shear diagram
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter5: Three-dimensional Equilibrium
Section: Chapter Questions
Problem 5.32P: Calculate the reaction at D for the structure described in Prob. 5.11.
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Can you explain how we get the numbers i underlined in blue for the shear diagram
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---
finalExamExamples.pdf
Page 1 of 14
SEP
13
Determine reactions
MB=O
-RA(4) +3(6)(3)+12(2)=0
RA=19,5kN
{Fy=0
RB-3/6)-12 +19,5=0
RB = 10.5KN
Cross-section equilibrium approach
O<x<2m/
3/4 √ √
280
13
415²
X(X)
19.5KN
Σty=0
Max) { -√(x)-3(x) = 0
V(x)=3(x)
IM=0
MQ) + 3x² = 0
M(x)=-3x²
*
1 < x <4m]
_MG)} {Fy=0
3km J 11vad) 2-V(x)-3x+19.5=0
V(x)=-3x+19.5
1
3kN/m
209
Str.
66
7
2
Screen Shot
S
V(x) 13.5
KN
-6-
3 kN/m
M(X), kN•m
ΣM=O
M(x) + 3x 2 - 195(x-2)=0
M(x) = -2X² +19.5(x-2)
2 m
-6
♫
ΔΑ
Screen Shot
7.5
15-
2 m
(+)
-4.5
tv A
12 kN
m
2 m
(---)
=-=-6 (2)
area under shear
diagram between
JC & A
? A
Screen Shot
4
Search
B
W
-10.5
13.5+7.5 (2)
2
Screen Shot
area shear
under Shear
+ diagrant
between
A&D
-4.5-10.5(2)
2
area
undershear
diagram
Jeen
M
Ơ
Wed Sep 13 5:32:57 PM
Screen Shot
1
Exam #3
Final Problem
2447
Homework #11 9B
Physics Midterm
Physics Midterm
#2
Rmd
R_Lab1 AVERAGE
INCOME.Rmd
▶
R_Lab1-AVERAGE-
INCOME.html](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faeefd442-7c64-4a51-8ed1-c0196ac6a13e%2F920499e4-5fe5-4524-ac16-f874aa98e1f6%2F1rouxyu_processed.png&w=3840&q=75)
Transcribed Image Text:Preview
File Edit View Go Tools Window Help
---
finalExamExamples.pdf
Page 1 of 14
SEP
13
Determine reactions
MB=O
-RA(4) +3(6)(3)+12(2)=0
RA=19,5kN
{Fy=0
RB-3/6)-12 +19,5=0
RB = 10.5KN
Cross-section equilibrium approach
O<x<2m/
3/4 √ √
280
13
415²
X(X)
19.5KN
Σty=0
Max) { -√(x)-3(x) = 0
V(x)=3(x)
IM=0
MQ) + 3x² = 0
M(x)=-3x²
*
1 < x <4m]
_MG)} {Fy=0
3km J 11vad) 2-V(x)-3x+19.5=0
V(x)=-3x+19.5
1
3kN/m
209
Str.
66
7
2
Screen Shot
S
V(x) 13.5
KN
-6-
3 kN/m
M(X), kN•m
ΣM=O
M(x) + 3x 2 - 195(x-2)=0
M(x) = -2X² +19.5(x-2)
2 m
-6
♫
ΔΑ
Screen Shot
7.5
15-
2 m
(+)
-4.5
tv A
12 kN
m
2 m
(---)
=-=-6 (2)
area under shear
diagram between
JC & A
? A
Screen Shot
4
Search
B
W
-10.5
13.5+7.5 (2)
2
Screen Shot
area shear
under Shear
+ diagrant
between
A&D
-4.5-10.5(2)
2
area
undershear
diagram
Jeen
M
Ơ
Wed Sep 13 5:32:57 PM
Screen Shot
1
Exam #3
Final Problem
2447
Homework #11 9B
Physics Midterm
Physics Midterm
#2
Rmd
R_Lab1 AVERAGE
INCOME.Rmd
▶
R_Lab1-AVERAGE-
INCOME.html
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