Carbonyl fluoride, COF2, is a chemical reagent useful in the synthesis of fluorinated organic compounds. The decomposition of COF2 occurs at high temperature and with a catalyst according to the following reaction: Part A 2 COF2(g) = CO2(g) + CF4(g) Determine the equilibrium constant at 675 K. Given that A,H = -47.5 kJ mol-1 and the equilibrium constant at 852 K is K = 7.14: O 7.13 O 7.16 O 1.23 34.6 O 41.5

Introduction to Chemical Engineering Thermodynamics
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Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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Carbonyl fluoride, COF2, is a chemical reagent useful in
the synthesis of fluorinated organic compounds. The
decomposition of COF2 occurs at high temperature and
with a catalyst according to the following reaction:
Part A
2 COF2(g) = CcO2(g) + CF4(g)
Determine the equilibrium constant at 675 K.
Given that A,HP = -47.5 kJ mol-1 and the equilibrium
constant at 852 K is K = 7.14:
7.13
7.16
1.23
O 34.6
41.5
Transcribed Image Text:Carbonyl fluoride, COF2, is a chemical reagent useful in the synthesis of fluorinated organic compounds. The decomposition of COF2 occurs at high temperature and with a catalyst according to the following reaction: Part A 2 COF2(g) = CcO2(g) + CF4(g) Determine the equilibrium constant at 675 K. Given that A,HP = -47.5 kJ mol-1 and the equilibrium constant at 852 K is K = 7.14: 7.13 7.16 1.23 O 34.6 41.5
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